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3 years ago

Find the missing measure

Mathematics

1 answer:

Margarita [4]3 years ago

5 0

The answer is 112. Angles that are adjacent are equal and the other two would be 68.

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Can you double a square with a straightedge and a compass?

sergejj [24]

I'd say yes. If you use the diagonal as a reference. Take the square and set your compass to the width of the diameter of the square. Now put it on the page and mark a point. Put the point of the compass on that mark and make another mark. Now you can connect the two marks with the straight edge and you have a line that, if you made a square with sides that long, it'd have 2x the area of the first one. That's because the diagonal is the square root of 2 larger than one side. Square the square root of 2 and you've got 2. You lust need to make a perpendicular line to the first one to get the box going.

8 0

3 years ago

HELP! Identify the equation of the circle that has its center at (-3, -4) and passes through the origin.

Lunna [17]

Answer:

Option B. (x+3) ^2+(y+4)^2=25

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

step 1

Find the radius of the circle

Remember that the distance of the center and any point on the circle is equal to the radius of the circle

Find the distance between the points (-3,-4) and (0,0)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute

$r=\sqrt{(0+4)^{2}+(0+3)^{2}}$

$r=\sqrt{(4)^{2}+(3)^{2}}$

$r=\sqrt{25}$

$r=5\ units$

step 2

Find the equation of the circle

$(x-h)^{2}+(y-k)^{2}=r^{2}$

the center is the point (-3,-4) and the radius is r=5 units

substitute

$(x+3)^{2}+(y+4)^{2}=5^{2}$

$(x+3)^{2}+(y+4)^{2}=25$

6 0

3 years ago

Help, brainliest to whoever answers

jok3333 [9.3K]

Answer: 45
Plug in 150 for s in the equation and solve

3 0

3 years ago

Read 2 more answers

Hello i would need help with this

Vika [28.1K]

if u download photomath and take a picture of each problem it will give u a solution to each problem along with the steps of how they got that answer

5 0

3 years ago

Read 2 more answers

A theatre has 15 seats in the first row, 20 seats in the second row, 25 seats in the third row, and so on. Write the linear equa

viktelen [127]

Answer: The answer is (n = 5r + 10).

Step-by-step explanation: Given that in a theatre, there are 15 seats in the first row, 20 seats in the second row, 25 seats in the third row, etc.

We are to write the linear equation that represents the number of seats 'n' in each row 'r'.

Now,

Number of seats in the 1st row = 15 = 5 × 3 = 5 × (1+2),

number of seats in the 2nd row = 20 = 5 × 4 = 5 × (2+2),

number of seats in the 3rd row = 25 = 5 × 5 = 5 × (3+2), etc...

Therefore, number of seats 'n' in the r-th row is given by the following linear equation -

n = 5 × (r+2), i.e., n = 5r + 10.

Thus, the required linear equation is n = 5r + 10.

7 0

3 years ago