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Gelneren [198K]
3 years ago
10

Solve for y 3x+2.75y=2(.625y+5)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0

3x+2.75y=2(0.625y+5)\\\\3x+2.75y=2(0.625y)+9(5)\\\\3x+2.75y=1.25y+45\ \ \ \ |-3x\\\\2.75y=1.25y+45-3x\ \ \ \ |-1.25y\\\\1.5y=45-3x\ \ \ \ \ |:1.5\\\\y=30-2x

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The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
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Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

                   is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

                   \frac{A+B+C+D+E}{5} =30.

On multiplying both side by 5.

                       A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

  Then :  1 +2+3+4+E =150

On simplification  10+E =150

On subtraction both side by 10 we get

                      E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.


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