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Gelneren [198K]
3 years ago
10

Solve for y 3x+2.75y=2(.625y+5)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0

3x+2.75y=2(0.625y+5)\\\\3x+2.75y=2(0.625y)+9(5)\\\\3x+2.75y=1.25y+45\ \ \ \ |-3x\\\\2.75y=1.25y+45-3x\ \ \ \ |-1.25y\\\\1.5y=45-3x\ \ \ \ \ |:1.5\\\\y=30-2x

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First twelve numbers<br> Add 15, subtract 10 (first term: 4)
astra-53 [7]

Answer:

1st- 4, 2nd- 9, 3rd- 14, 4th- 19, 5th- 24, 6th- 29, 7th-  34, 8th- 39, 9th- 44, 10th- 49, 11th- 54, 12th-59

Step-by-step explanation:

1st- 4

2nd- 4+15-10= 9

3rd- 9+15-10=14

4th- 14+15-10=19

5th- 19+15-10=24

6th- 24+15-10=29

7th-  29+15-10=34

8th- 34+15-10=39

9th- 39+15-10=44

10th- 44+15-10=49

11th- 49+15-10=54

12th-54+15-10=59

4 0
3 years ago
Find the product 6x500=6x blank hundreds
grandymaker [24]
500? If you're trying to find x...
4 0
3 years ago
Explain how to get the variable alone in the equation. a ÷ 11 =5​
denpristay [2]

Answer:

Multiply both sides by 11 to isolate the variable.

Step-by-step explanation:

a = 55

7 0
3 years ago
Research the keywords "shaping by successive approximation" on the Internet. Shaping is a
NNADVOKAT [17]

Answer and Step-by-step explanation:

The concept of "shaping" is: "a term of behaviur that refers to slowly shaping or educating an organ to execute a particular response by improving any responses that come even close to the desired answer.

Let's take one rat example.

Here, in an experiment, a researcher may use moulding technique to coach a rat to push a lever.

To begin with, the researcher may award the rat if it does any movement in the lever direction at all. The rat will then simply take a step towards to the lever to be rewarded. Likewise, as the rat moves over to the lever and so forth, the rat also gets a reward before just pushing the lever generates reward.

Here the behaviour of the rat was 'formed' in order to make it push the lever. According to the example, any time the rat is awarded, it is praised for a "successive approximation" or for behaving in a manner that is nearer to the desired behaviour or result.

Likewise, algebraic equations are also progression steps and step-by - step progression allows solve the issue.

8 0
3 years ago
Can someone solve this?
ladessa [460]
  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|

For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

6 0
4 years ago
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