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Gelneren [198K]
3 years ago
10

Solve for y 3x+2.75y=2(.625y+5)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0

3x+2.75y=2(0.625y+5)\\\\3x+2.75y=2(0.625y)+9(5)\\\\3x+2.75y=1.25y+45\ \ \ \ |-3x\\\\2.75y=1.25y+45-3x\ \ \ \ |-1.25y\\\\1.5y=45-3x\ \ \ \ \ |:1.5\\\\y=30-2x

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R is the midpoint of QS, if QR=2x and RS=x+3, what is RS?
lbvjy [14]
Q -------------R------------S

suppose this is your line,

R is the mid point

and it's given that

QR = 2x
and
RS = x+3

as R is the mid point of QS
so,
QR = RS
then,
2x = x + 3
2x - x =3
x = 3


as,
it's given that RS = x + 3
then,
RS = 3 + 3
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5 0
3 years ago
1<br> Calculate the area of the<br> rectangle.<br> N<br> 11 m <br> 5 1/4 m
antoniya [11.8K]

Answer:

57.75 or 57.8

Step-by-step explanation:

5 0
2 years ago
It was -5 degrees Celsius in Copenhagen and -12 degrees Celsius in Oslo. Which city was colder? *
PtichkaEL [24]

Answer: Oslo was colder

Step-by-step explanation: The other one was -5 and this won is -12 so Oslo is colder!! Hope it helped! :)

8 0
2 years ago
Among 500 freshmen pursuing a business degree at a university, 311 are enrolled in an economics course, 243 are enrolled in a ma
Allushta [10]

Solution :

Let A = Economics, B = Mathematics

n(A) = 311, n(B) = 243, $n(A \cap B) = 135$

a). So, $n(A \cup B) = n(A) +n(B) - n(A \cap B)$

                     = 311 + 243 - 135

                     = 419

b). n(A only) = 311 - 135

                   = 176

     n(B only) = 243 - 135

                   = 108

Exactly one of these two courses

  $=\frac{176+108}{500}$

  = 0.568

c). Neither economics nor mathematics

    $=\frac{500-419}{500} $

  $=\frac{81}{500}$

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7 0
3 years ago
1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
3 years ago
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