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nirvana33 [79]
3 years ago
15

Find the area of a circle with a circumference of 6 pi

Mathematics
2 answers:
N76 [4]3 years ago
7 0
To find the circumference of a circle you use the formula C=pi*(radius*radius). If you know that the cuircumference is 6 pi, you first plug that in to solve for the radius.
6pi=pi*(r*r)
6pi/pi=(r*r)
Square root of(6pi/pi)=r
2.45=r
Then to find the area you use the formula A=pi*(r*r) which is
A=Pi*(2.45*2.45)
A=6pi or 18.85
elena-14-01-66 [18.8K]3 years ago
3 0
The circumference formula is 2\pir and if the circumference is 6pi then the radius is 3. apply that to the area fromula ( \pir^2 ) and you get 9\pi
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Answer:

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Step-by-step explanation:

we are given that

\displaystyle P =  \left(x,  - \frac{  \sqrt{7} }{4}  \right)

we want to figure out x

remember that,

In <u>unit</u><u> </u><u>circle</u> x coordinate is considered cos and y coordinate is considered sin

so in order to figure out x we should figure out the value of <u>cos</u> to do we can consider <u>Pythagoras</u><u> trig</u><u> </u><u>indentity</u>

given by

\displaystyle  \sin ^{2} ( \theta)  +  {  \cos}^{2} ( \theta) = 1

we are given sin=-√7/4 thus

substitute:

\displaystyle   \left( - \frac{ \sqrt{7}  }{4}  \right) ^{2}   +  {  \cos}^{2} ( \theta) = 1

simplify square:

\displaystyle  \frac{7}{16}  +  \cos ^{2} ( \theta)  = 1

move left hand side expression to right hand side and change its sign:

\displaystyle   \cos ^{2} ( \theta)  = 1 -  \frac{7}{16}

simplify Substraction:

\displaystyle   \cos ^{2} ( \theta)  =  \frac{9}{16}

square root both sides:

\displaystyle   \cos ^{} ( \theta)  =   \pm\frac{3}{4}

since in unit circle cos is x and P belongs to Q:IV negative cos isn't applicable

hence,

\displaystyle   x =   \frac{3}{4}

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