Point R is the midpoint of FE¯¯¯¯¯ , so the coordinates of point R are (3a, b).
In △DEF , the length of the base, DF¯¯¯¯¯ , is
4a, and the height is 2b, so its area is
1/2×4a×2b = 4ab.
In △QRP , the length of the base, QR¯¯¯¯¯ , is
3a-a = 2a, and the height is b, so its area is 1/2×2a×b = ab .
Comparing the expressions for the areas proves that the area of the triangle created by joining the midpoints of an isosceles triangle is one-fourth the area of the larger isosceles triangle.
20,27,34
The common difference is 7
This is. Pemdas. P is puntion. M mutupaTy d division a. Aadd s subtraant
Answer:
-3<
2-x
Step-by-step explanation:
Answer:
(fg)(x) = 6x³ - 2x² + 12x - 4
Step-by-step explanation:
( f g ) ( x ) = f ( x ) * g ( x )
f(x) = 2x² + 4
g(x) = 3x – 1
( f g ) ( x ) = (2x² + 4) (3x – 1)
= 6x³ - 2x² + 12x - 4
