Answer:
(x+5)^2+(y-12)^2=256
Step-by-step explanation:
Comparing the given (x+5)^2+(y-12)^2=256
to (x - h)^2 + (y - k)^2 = r^2,
we see that h must be -5, k must be 12 and r must be 16. This is the desired equation of the circle with center at (-5, 12) and radius 16.
i’m pretty positive you would just subtract!
<u><em>Answer:</em></u>
SAS
<u><em>Explanation:</em></u>
<u>Before solving the problem, let's define each of the given theorems:</u>
<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle
<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle
<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle
<u>Now, let's check the given triangles:</u>
We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
This means that the two triangles are congruent by <u>SAS</u> theorem
Hope this helps :)
