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3 years ago

The graph of the function f(x) is shown. Which graph represents the function f(2x)

Mathematics

1 answer:

slava [35]3 years ago

8 0

Answer:

It should be the top left graph where there is point (1,1) and (-1, -1) y = 1/x

Step-by-step explanation:

from the original graph, I see:

f(x) = 2/x because f(2) = 1 = 2/2

f(1/4)= 2/(1/4) = 2

...

so then f(2x) compresses f(x) horizontally by a factor of 2

so f(2x) = 2/(2x) = 1/x

You might be interested in

Find the amount of money in an account after 9 years if $8,000 is

Anna35 [415]

Answer:

8,000(1+.09/4) to the 4×9 power

8,000(1.0225) to the 36 power

8,000(2.227816)

answer is $17,822.53

7 0

3 years ago

Simplify!! Thank you :)

Nezavi [6.7K]

Combine like terms.

$2 {x}^{2} + 8 {x}^{2} = 10 {x}^{2}$

$x + 7x = 8x$

$4 + ( - 3) = 1$

So, the answer would be

$10 {x}^{2} + 8x + 1$

8 0

3 years ago

You invest $1600 in an account paying 5% interest compounded daily. What is the account's effective annual yield? Assume 360 day

Pavlova-9 [17]

Answer:

5.13%.

Step-by-step explanation:

Amount accumulated in 1 year

= 1600(1 + 0.05/360)^360

= $1682.03

Account's effective annual yield

= 82.03 * 100 / 1600 %

= 5.13%.

3 0

3 years ago

Attend to precision. The equation y − 160 = 40(x − 1) represents the height in feet, y, of a hot-air balloon x minutes after the

sineoko [7]

Answer:

Step-by-step explanation:

a. the balloon is rising because the slope is positive. the slope is 40 because when you simplify y-160 = 40 (x-1) it gets you y = 40x +120

b. it is ascending (bc positive) at 40 feet per minute

c. it was at 120 feet in the air. The 120 is the y intercept

6 0

3 years ago

Karen is starting a career as a professional wildlife photographer and plans to photograph Canadian Geese at one of the staging

balandron [24]

Answer:

$5000*0.816 = $4082

Step-by-step explanation:

It's a strange question, but based on the statement and the question it sounds like it's a poisson distribution:

* For 3 days she was able to get 2 good shots (<em>typical of that time of the year</em>)

* Good shots happen randomly

* Each day is independent of another

Let's call 'p' the probability that she makes a good shot per day

Let's call 'n' the number of days Karen is taking shots.

So, if in 3 days he got 2 good shots and that is typical at that time of the year, then the expected value for the number of good shots (X) is:

$E(x)=\frac{2}{3}$

For a Poisson distribution $E (x)=\lambda\\\lambda= np$

So:

$\lambda =\frac{2}{3}$

For a Poisson distribution the standard deviation is:

$\sigma = \sqrt{\lambda}\\\sigma = \sqrt{\frac{2}{3}}$

$\sigma = 0.816$ this is the standard deviation for the number of buentas taken.

So the standard deviation for income is the price of each shot per sigma

$5000*0.816 = $4082, which is the desired response.

3 0

3 years ago