If the coefficient 2 is placed in front of the product tetraiodine nonaoxide (I4O9), then, how many atoms of each element must b

Question

3 years ago

12

e accounted for on the otherwise of the equation

1 answer:

gogolik [260] · Answer 1 · 2022-06-21T12:08:00+03:00

Answer:

Number of iodine atoms = 2 × 4 = 8

Number of oxygen atoms = 2 × 9 = 18

Explanation:

Coefficient 2 is placed in front of the product tetraiodine nonaoxide:

= $2I_4O_9$

Number of iodine atom in a single molecule tetraiodine nonaoxide = 4

Number of oxygen atoms in a single molecule tetraiodine nonaoxide = 9

Coefficient 2 is placed in front of the product tetraiodine nonaoxide:

= $2I_4O_9$

Number of iodine atoms = 2 × 4 = 8

Number of oxygen atoms = 2 × 9 = 18