If the coefficient 2 is placed in front of the product tetraiodine nonaoxide (I4O9), then, how many atoms of each element must b
1 answer:
Answer:
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18
Explanation:
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
=
Number of iodine atom in a single molecule tetraiodine nonaoxide = 4
Number of oxygen atoms in a single molecule tetraiodine nonaoxide = 9
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
=
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18
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