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xenn [34]
3 years ago
15

The density of liquid mercury is 13.69 g/cm 3 . how many atoms of mercury are in a 17 ml sample? use "e" for "×10" and report th

e answer to at least 4 significant figures.
Chemistry
1 answer:
aivan3 [116]3 years ago
3 0
         step  one;  calculate  mass
Mass=density   x volume
    1ml=1cm^3
   13.69g/cm^3  x  17  cm^3=232.73g

  step  2;  calculate  the   number of  moles  of   mercury
(232.73g/200.59g/mol)(molar  mass  of mercury=  1.1602moles
  
by  use   of  avogdros  law
1moles =6.023E23  atoms
what about  1.1602moles
=1.1602 x 6.023E23=  6.988E23atoms



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Answer:

Charge is conserved due to the groups in which Lithium and Chlorine are located in the periodic table of the elements.

Explanation:

In the reaction Li + Cl - > LiCl, we can examine the groups in which Li and Cl are found in the periodic table of the elements. Lithium appears in Group 1A, or the alkali metals group, indicating that it carries a charge of +1. Chlorine appears in Group 7A, or the halogen group, indicating that it carries a charge of -1. Because LiCl's constituent elements carry the same charges as previously mentioned, LiCl will have an overall charge of 0.

The chemical equation can then be rewritten as Li^{+} + Cl^{-} - > LiCl, which, if looking at the individual charges of Li and Cl in lithium chloride, becomes Li^{+} + Cl^{-} - > Li^{+}Cl^{-}. Adding the charges on the reactant and product sides of this chemical equation gives us zero in both locations, meaning that we have a charge of 0 on the reactant side and a charge of 0 on the product side. This indicates that charge is conserved in this reaction.

Another way to look at this is expressed in the valence electrons of Li and Cl. Li has an electron configuration of 1s^{2}2s^{1}, where the n = 2 electron shell has one of eight total electrons needed to fill the valence shell. This means that Li will easily lose one electron in order to have an electron configuration where the n = 1 electron shell is full, 1s^{2}, and become the Li^{+} ion. Similarly, Cl has an electron configuration of 1s^{2}2s^{2}2p^{6}3s^{2}3p^{5} (or [Ne]3s^{2}3p^{5}), meaning that the n = 3 electron shell is one electron away from becoming complete. Cl will easily gain one electron to have the electron configuration [Ne]3s^{2}3p^{6} (or [Ar]) in order to have an electron configuration where the n = 3 electron shell is full, 3s^{2}3p^{6}, and become the Cl^{-} ion. Thus, when Li and Cl bond, Li will lose the electron [1, 0, 0, +\frac{1}{2}] and transfer it to Cl, where it will become the electron [3, 1, 1, -\frac{1}{2}], thus conserving charge, as there is an equal total number of electrons before and after the reaction.

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Ai. A is called nucleus

Aii. B is called electron shell

B. The name of the element is Neon and the symbol of the element is Ne.

Ci. The atomic mass of the element is 20.

Cii. The atomic number of the element is 10

Di. The element belongs to group 18.

Dii. The element belongs to period 2.

E. The element has a valency of 8

A. Determination of the name of A and B

In the diagram given above, A is called the nucleus because it contains the neutrons and the protons of the atom.

B is called the electron shell because it contains the electrons of the atoms

B. Determination of the name and symbol of the element.

From the diagram given above,

The element has 10 protons. This simply means that the atomic number of the element is 10.

Comparing the atomic number of the element with those in the periodic table, the element is Neon with a symbol of Ne.

C. Determination of the atomic mass and atomic number.

Ci. Determination of the mass number

Proton = 10

Neutron = 10

<h3>Mass number =?</h3>

Mass number = Proton + Neutron

Mass number = 10 + 10

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Thus, the atomic mass of the element is 20.

Cii. Determination of the atomic number.

The atomic number of an element is simply the number of protons in the atom of the element.

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Therefore,

Atomic number = proton = 10

Thus, the atomic number of the element is 10

D. Determination of the group and period.

Di. The group to which an element belongs to can be obtained by simply calculating the number of electrons in the outermost shell of the atom.

From the diagram given above, the outermost shell has 8 electrons. This suggest that the element has completely filled outermost shell.

Therefore, the element belongs to group 18 (i.e the noble gas)

Dii. The number of electron shell talks about the period to which and element belongs to.

From the diagram given above, the element has 2 electron shells.

Therefore, the element belongs to period 2

E. Determination of the valence electron(s)

The valence electron(s) is the number of electrons in the outermost shell of the atom.

From the diagram given above,

The outermost shell has 8 electrons.

Therefore, the element has 8 valence electrons

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At sea level, the atmospheric pressure is very high. With altitude, the air becomes thinner and atmospheric pressure becomes lower.

With increasing altitude, the low atmospheric pressure makes the boiling point lower as a result of the decreasing pressure on the vapor.

The boiling point can then easily be reached at higher altitudes.

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