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xenn [34]
3 years ago
15

The density of liquid mercury is 13.69 g/cm 3 . how many atoms of mercury are in a 17 ml sample? use "e" for "×10" and report th

e answer to at least 4 significant figures.
Chemistry
1 answer:
aivan3 [116]3 years ago
3 0
         step  one;  calculate  mass
Mass=density   x volume
    1ml=1cm^3
   13.69g/cm^3  x  17  cm^3=232.73g

  step  2;  calculate  the   number of  moles  of   mercury
(232.73g/200.59g/mol)(molar  mass  of mercury=  1.1602moles
  
by  use   of  avogdros  law
1moles =6.023E23  atoms
what about  1.1602moles
=1.1602 x 6.023E23=  6.988E23atoms



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LenaWriter [7]

To solve this problem, we can use the Henderson-Hasselbalch Equation which relates the pH to the measure of acidity pKa. The equation is given as:<span>

<span>pH = pKa + log ([base]/[acid])                ---> 1</span></span>

Where,

[base] = concentration of C2H3O2 in molarity or moles

<span>[acid] = concentration of  HC2H3O2 in molarity or moles</span>

 

For the sake of easy calculation, let us assume that:

[base] = 1

[acid] = x

<span>
Therefore using equation 1,
4.24 = 4.74 + log (1 / x) 

<span>log (1 / x) = - 0.5

1 / x = 0.6065 </span></span>

x = 1.65<span>

The required ratio of C2H3O2 /HC2H3O2 <span>is 1:1.65 or 3:5. </span></span>
3 0
3 years ago
What chemical reactions occur in a Nelson's cell? ​
Cerrena [4.2K]

Explanation:

The graphite anodes are suspended into the brine. During electrolysis, Cl ions are oxidized at the anode and chlorine gas goes out of the cell, while sodium ions are reduced at the mercury cathode forming sodium amalgam. ... Hydrogen gas is obtained as a by–product at the cathode.

8 0
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When Truman walks across the tile floor in his kitchen, the sound of his shoes is loud and sharp. Which of the following best de
Alexxx [7]

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Explanation:

6 0
2 years ago
Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and
blondinia [14]

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon

For Hydrogen:

=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen

For Oxygen:

=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon

For Hydrogen:

\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen

For Oxygen:

\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen

Thus, the empirical formula is HCO₂

4 0
3 years ago
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natita [175]

Answer:

Explanation:

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