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3 years ago

Rose's bank account y = 8x+ 50 what is the rate and what does Y-intercept

Mathematics

1 answer:

quester [9]3 years ago

6 0

Explanation:

The rate is 8. It's attached to the "x". When graphed, 8 is the slope.

The y-intercept represents the initial value, or the starting amount of money in Rose's bank account.

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Every 8th customer gets a $50 gift certificate.

cluponka [151]

The answer is the 24th customer
You need to find the LCM of 6 and 8.
If you prime factorize both you get…
6=(2)(3)
8=2^3
So 2^3, which is 8 times 3 is 24.
The answer is the 24th customer.

3 0

2 years ago

Evaluate 5p to the power of 3 when p = -2

Mrac [35]

5(-2)^3 5(-2) is -10 to the power of 3 is -1000

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3 years ago

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State the property that justifies each statement:1. If 80 mA, then me = 802. If RS - TU and TU = YP, then RS = YP2.3. If 7x 28,

BabaBlast [244]

Question 3

if 7x = 28

divide both sides by 7

7x/7 = 28/7

x = 4

This is division property of equality

Question 1

if angle m is 80 degrees the m = 80 degrees

this can be a congruent angles or alternate angles are equal

this is symmetric property of equality

Question 5

m1 = 30 and mz1 = m2, then m2 = 30

this property is transitive property of equality

Question 2

if RS - TU and TU =YP, then RS = YP

this means you can substitute RS with YP

then we have our new expression as

YP - YP

this is substitution property of equality, this is because we are substituting a function with another function

4 0

1 year ago

What is 1/5 expressed as a percent

coldgirl [10]

1/5 x 100 = 20%

Answer: 20%

4 0

3 years ago

Read 2 more answers

4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail

Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

$h^{-1}(x)=\sqrt{\frac{x+1}{3}}$ ⇒ answer D

Step-by-step explanation:

* Lets explain how to find the inverse of a function

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = $f^{-1}(x)$

* Lets use these steps to solve the problems

∵ $f(x)=\sqrt{x-3}$

∵ f(x) = y

∴ $y=\sqrt{x-3}$

- Exchange x and y

∴ $x=\sqrt{y-3}$

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by $f^{-1}(x)$

∴ $f^{-1}(x)=x^{2}+3$

∵ g(x) = x² + 3

∴ $f^{-1}(x)=g(x)$

∴ The functions are inverses to each other

* Now lets find f(g(x))

- To find f(g(x)) substitute x in f(x) by g(x)

∵ $f(x)=\sqrt{x-3}$

∵ g(x) = x² + 3

∴ $f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x$

∴ f(g(x)) = x

∴ The functions are inverses; f(g(x)) = x

* Lets find the inverse of h(x)

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ $\frac{x + 1}{3}=y^{2}$

- Take √ for both sides

∴ ± $\sqrt{\frac{x+1}{3}}=y$

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ $\sqrt{\frac{x+1}{3}}=y$

- replace y by $h^{-1}(x)$

∴ $h^{-1}(x)=\sqrt{\frac{x+1}{3}}$

4 0

3 years ago