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Anastaziya [24]
3 years ago
5

Find the domain of the function. (Enter your answers using interval notation.) f(s, t) = square root of s^2+t^2.

Mathematics
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

S=\{\forall \,s,t\in \mathbb{R}|s\in(-\infty,+\infty), t\in(-\infty,+\infty)\}

Step-by-step explanation:

Let be f(s,t) = \sqrt{s^{2}+t^{2}}, the range of a square root compehends the subset of positive real numbers plus zero. Likewise, the range of the square of any number has the same subset with all real set as domain. As square root encloses a sum of squares, the domain of the function is:

S=\{\forall \,s,t\in \mathbb{R}|s\in(-\infty,+\infty), t\in(-\infty,+\infty)\}

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Rsm question please explain<br> The question is in the picture
strojnjashka [21]

A triangle is a three-edged polygon with three vertices. ΔAKE and ΔCKP are congruent.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angle of a triangle is always equal to 180°.

In ΔABC, since AB≅BC, therefore, the triangle will be an isosceles triangle, and the measure of ∠A ≅ ∠C, using the base angle theorem.

Now In ΔAKE and ΔCKP,

∠A ≅ ∠C {Proved above}

∠AKE ≅ ∠CKP {Given}

AK ≅ KC {Given }

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Hence, ΔAKE and ΔCKP are congruent.

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