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Anastaziya [24]
3 years ago
5

Find the domain of the function. (Enter your answers using interval notation.) f(s, t) = square root of s^2+t^2.

Mathematics
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

S=\{\forall \,s,t\in \mathbb{R}|s\in(-\infty,+\infty), t\in(-\infty,+\infty)\}

Step-by-step explanation:

Let be f(s,t) = \sqrt{s^{2}+t^{2}}, the range of a square root compehends the subset of positive real numbers plus zero. Likewise, the range of the square of any number has the same subset with all real set as domain. As square root encloses a sum of squares, the domain of the function is:

S=\{\forall \,s,t\in \mathbb{R}|s\in(-\infty,+\infty), t\in(-\infty,+\infty)\}

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IRISSAK [1]

Answer:

The\ simplified\ form\ of\ the\ \frac{5 + 6i}{4 + 6i}\ is\ \frac{56-6i}{52}.

Option (C) is correct .

Step-by-step explanation:

As the expression given in the question as follows.

= \frac{5 + 6i}{4 + 6i}

Now rationalize the expression.

= \frac{5 + 6i\times 4 - 6i}{4 + 6i\times 4 - 6i}

Using the formula

a² - b² = (a - b) (a + b)

Using in the above

= \frac{5 + 6i\times 4 - 6i}{(4)^{2} - (6i)^{2}}

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As i² = -1

= \frac{20-30i+24i+36}{16 + 36}

= \frac{56-6i}{52}

Therefore\ the\ simplified\ form\ of\ the\ \frac{5 + 6i}{4 + 6i}\ is\ \frac{56-6i}{52}.

Option (C) is correct .

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