Question

Reduce the following fraction: -32abc/64a^2bc^2

Answer 1

Answer:

$-\dfrac{1}{2ac}$

Step-by-step explanation:

Given:

$\dfrac{-32abc}{64a^2bc^2}$

Reduce this fraction.

Work with numbers and different letters separately:

1. Numbers:

$\dfrac{-32}{64}=-\dfrac{32}{32\cdot 2}=-\dfrac{1}{2}$

2. Letter a:

$\dfrac{a}{a^2}=\dfrac{a}{a\cdot a}=\dfrac{1}{a}$

3. Letter b:

$\dfrac{b}b}=1$

4. Letter c:

$\dfrac{c}{c^2}=\dfrac{c}{c\cdot c}=\dfrac{1}{c}$

Hence,

$\dfrac{-32abc}{64a^2bc^2}=-\dfrac{1}{2}\cdot \dfrac{1}{a}\cdot \dfrac{1}{c}=-\dfrac{1}{2ac}$

Answer 2

Answer:

-1/(2ac)

Step-by-step explanation:

-32/64=-1/2

the b's cancel each other out,

leaving you with ac on the denominator.