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4 years ago

Planes have edges true or false

Mathematics

1 answer:

Cerrena [4.2K]4 years ago

6 0

False planes do not have edges.

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In a triangle ABC, AB= BC, Bc=CA what is the measurement of <A

goldfiish [28.3K]

Answer:

60°

Step-by-step explanation:

If AB=BC=CA, it means ABC is an equilateral triangle which all three sides are equal.
Thus, all three internal angles are also congruent to each other and are each 60°.

8 0

4 years ago

Read 2 more answers

Answer the ones you want to. At least answer one…

Artyom0805 [142]

Answer:

9. First Five terms

If n=0. Then,

$\frac{4(0) - 5}{2}$

$\frac{0 - 5}{2} = \frac{ - 5}{2}$

If n=1. Then,

$\frac{4(1) - 5}{2}$

$\frac{4 - 5}{2} = \frac{ - 1}{2}$

If n=2. Then,

$\frac{4(2) - 5}{2}$

$\frac{8 - 5}{2} = \frac{3}{2}$

If n=3. Then,

$\frac{4(3) - 5}{2}$

$\frac{12 - 5}{2} = \frac{7}{2}$

If n=4. Then,

$\frac{4(4) - 5}{2}$

$\frac{16 - 5}{2} = \frac{11}{2}$

If n=5. Then,

$\frac{4(5) - 5}{2}$

$\frac{20 - 5}{2} = \frac{15}{2}$

If n=6. Then,

$\frac{4(6) - 5}{2}$

$\frac{24 - 5}{2} = \frac{19}{2}$

7 0

3 years ago

What is -4y-3=5-3y+6-19

Rasek [7]

Answer:

5 =y

Step-by-step explanation:

-4y-3=5-3y+6-19

Combine like terms

-4y -3 = -3y -8

Add 4y to each side

-4y+4y -3 = -3y+4y -8

-3 = y -8

Add 8 to each side

-3+8 = y-8+8

5 =y

6 0

3 years ago

Graph the parabola. y=x^2-4x+2

qwelly [4]

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Vertex:

(2,−2)

Focus:

(2,−74)

Axis of Symmetry:

x=2

6 0

3 years ago

Read 2 more answers

Compute the compositions H ∘ J and J ∘ H to determine whether or not J and H are inverses. (Simplify your answers completely.) H

sdas [7]

Answer:

Remember, if H(x) and J(x) are functions, then $(H\circ J)(x)=H(J(x))$ . And G(x) is the inverse function of H(x) if $(G\circ H)(x)=(H\circ G)(x)=x$

With $H(x)=\frac{x+1}{x-1},\; J(x)=\frac{x+1}{x-1}$ . Since H and J are the same function, then

$(H\circ J)(x)=(J\circ H)(x)=J(\frac{x+1}{x-1})=\\=\frac{\frac{x+1}{x-1}+1}{\frac{x+1}{x-1}-1}=\frac{\frac{x+1+x-1}{x-1}}{\frac{x+1-x+1}{x-1}}=\frac{2x(x-1)}{2(x-1)}=x$ .

Since $(J\circ H)(x)=(H\circ J)(x)=x$ , then H and J are inverses.

3 0

3 years ago