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Schach [20]
3 years ago
8

If f(x) = x^2 + 1 and g(x) = 3x + 1, find 2f(1) + 3g(4)

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0
\bf \begin{cases}
f(x) = x^2 + 1\\\\
g(x) = 3x + 1
\end{cases}\quad 
\begin{cases}
f(1)=\boxed{1}^2+1\to &\boxed{?}\\\\
g(4)=3(\boxed{4})+1\to &\boxed{?}
\end{cases}
\\\\\\
2f(1)=2\cdot \boxed{?}\qquad \qquad 3g(4)=3\cdot \boxed{?}
weeeeeb [17]3 years ago
3 0
2f(1)+3g(4)=43

2*(1^2+1)=4
3*(3(4)+1)=39

4+39=43 
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Consider the following division of polynomials.
Bond [772]

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x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

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What we showed here is that

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To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

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