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vampirchik [111]
4 years ago
15

WILL GIVE BRAIN LIST!! :))

Mathematics
2 answers:
zlopas [31]4 years ago
8 0

Answer:

Step-by-step explanation:

Dominik [7]4 years ago
4 0

Answer:

690

Step-by-step explanation:

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a collector has 80 jackeys and 125 shirts she wants to maintain ratio in her collection but she needs to sell some of her items
Irina18 [472]

Answer:

25

Step-by-step explanation:

Well, we need to simplify this. we have a ratio of 80:125.

As these numbers end in either 0 or 5, we know they are divisible by 5.

By dividing these by five, our ratio becomes 16:25.

As we have 16 jackets, we know we must need to sell 25 jackets to maintain the ratio.

8 0
3 years ago
You shouldn't get this question wrong, right?
uranmaximum [27]

Answer:

You have THREE OR 3 APPLES

4 0
3 years ago
Read 2 more answers
Which statement illustrates the identity property of multiplication
Marina86 [1]
0000000000090000$0000770098908790087
6 0
3 years ago
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Which inequality represents all the solutions of 10(3x + 2) > 7(2x − 4)?
Mrrafil [7]

Answer:

x>-3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
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