There are 7 chairs in each row length.
Step-by-step explanation:
Let number of chairs in 1 row be 'x'.
Let total number of chairs be 'y'.
Given:
Hue can form 6 rows of a given length with 3 chairs left over.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 6 plus number of chairs which is left which is 3.
Framing in equation form we get.
Also Given:
Hue can form 8 rows of that same length if she gets 11 more chairs.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 8 minus number of chairs which is required more which is 11.
Framing in equation form we get.
From equation 1 and equation 2 we can say that L.H.S is same.
So according to law of transitivity we get;
Combining like terms we get;
Using Subtraction and Addition property we get;
Now Using Division Property we will divide both side by 2.
Hence there are 7 chairs in each row length.
Answer:
where n∈Z.
Step-by-step explanation:
2sin²x-1; ⇒ sin²x=1/2;
![\left[\begin{array}{ccc}sinx=-\frac{1}{\sqrt{2}} \\sinx=\frac{1}{\sqrt{2}} \end{array} \ = > \ \left[\begin{array}{ccc}x=(-1)^{l+1}\frac{\pi }{4}+\pi l \\x=(-1)^k\frac{\pi }{4}+\pi k \end{array} \ = > x=\frac{\pi }{4} +\frac{\pi }{2}n, \ n-Z.](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dsinx%3D-%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%20%5C%5Csinx%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%20%5Cend%7Barray%7D%20%5C%20%3D%20%3E%20%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%3D%28-1%29%5E%7Bl%2B1%7D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%2B%5Cpi%20l%20%5C%5Cx%3D%28-1%29%5Ek%5Cfrac%7B%5Cpi%20%7D%7B4%7D%2B%5Cpi%20k%20%5Cend%7Barray%7D%20%5C%20%3D%20%3E%20x%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%20%2B%5Cfrac%7B%5Cpi%20%7D%7B2%7Dn%2C%20%5C%20n-Z.)
We know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
so
P=size of the event space/size of the sample space
in this problem
size of the sample=9-------> set. {2, 4, 6, 9, 16, 44, 51, 60, 78}
size of the event space=4---->number less than 10--> {2, 4, 6, 9}
P=4/9
the answer is
<span>P(< 10) = 4/9</span>