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3 years ago

Which graph show the solution set for -5/2x -3<2

Mathematics

1 answer:

Oliga [24]3 years ago

5 0

It is less than two, so it has to be going in the direction that is below two. There is a line under the < so the dot should be filled. The answer is the third from the top. “Choice C”

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Babies born after a gestation period of 32-35 weeks have a mean weight of 2700 grams and a standard deviation of 700 grams, whil

Nutka1998 [239]

Answer:

The 33 week gestation period baby has the higher z-score, so he weighs more relative to other babies of the same gestation period.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Who weighs more relative to other babies of the same gestation period?

Whoever has the higer z-score

33 - week baby.

Babies born after a gestation period of 32-35 weeks have a mean weight of 2700 grams and a standard deviation of 700 grams. A 33-week gestation baby weighs 2950 grams.

We have to find z when $\mu = 2700, \sigma = 700, X = 2950$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2950 - 2700}{700}$

$Z = 0.357$

40-week baby

Mean weight of 3000 grams and a standard deviation of 490 grams. 40-week gestation baby weighs 3150 grams.

We have to find Z when $\mu = 3000, \sigma = 490, X = 3150$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3150 - 300}{490}$

$Z = 0.306$

The 33 week gestation period baby has the higher z-score, so he weighs more relative to other babies of the same gestation period.

6 0

4 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

2 years ago

(MARKING BRAINLIEST!) Jeremiah read 10 books in 6 months. Fill out a table of equivalent ratios and plot the

navik [9.2K]

(0,3) (10,6) (40,15)

8 0

3 years ago

Perform the indicated operation to write given polynomial in standard form: (2x^3 − 6x^2 − 7x − 2) +(x^3 +x^2 +6x − 12)

Kipish [7]

Answer:

$\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=3x^3-5x^2-x-14$

Step-by-step explanation:

To add the polynomials

Remove parentheses:

$\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=2x^3-6x^2-7x-2+x^3+x^2+6x-12$

Group like terms:

$=2x^3+x^3-6x^2+x^2-7x+6x-2-12$

Add similar elements:

$=3x^3-6x^2+x^2-7x+6x-2-12\\=3x^3-5x^2-7x+6x-2-12\\=3x^3-5x^2-x-2-12\\=3x^3-5x^2-x-14$

The Standard Form for writing down a polynomial is to put the terms with the highest degree first,its term of 2nd highest is 2nd etc..

In our case the standard form is

$\left(2x^3-6x^2-7x-2\right)+\left(x^3+x^2+6x-12\right)=3x^3-5x^2-x-14$

3 0

3 years ago

Simplify this expression: g-3(f-g)-2f

vodomira [7]

Answer:

4g-5f

Step-by-step explanation:

g-3(f-g)-2f=g-3f+3g-2f=4g-5f

5 0

4 years ago