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shtirl [24]
4 years ago
8

Simplify this expression: g-3(f-g)-2f

Mathematics
1 answer:
vodomira [7]4 years ago
5 0

Answer:

4g-5f

Step-by-step explanation:

g-3(f-g)-2f=g-3f+3g-2f=4g-5f

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A farmer is building a fence to enclose a rectangular area against an existing wall, shown in the figure below.
mr Goodwill [35]

9514 1404 393

Answer:

  3362 ft²

Step-by-step explanation:

As we saw in brainly.com/question/22284853, the long side of the area will be half the length of the fence: 82 feet. The remaining two sides will be 41 feet each, so the largest area that can be enclosed is ...

  A = LW

  A = (82 ft)(41 ft) = 3362 ft²

7 0
3 years ago
SOMEONE PLEASE HELP!!!<br> what is the value of x? <br> A.15<br> B.25<br> C.30<br> D.35
Amiraneli [1.4K]
The answer is D, 35 degrees. The 35 degree angle and angle x are opposite interior angles and are therefore congruent in measure. 
4 0
3 years ago
Read 2 more answers
Esther ate seven less than six times as many jelly beans as Jake. Esther ate 77 jelly beans. How many jelly beans did Jake eat?
anygoal [31]
462 should be correct sorry if not
4 0
3 years ago
Read 2 more answers
Using the figure to the right, if RSTU is a rhombus, find measure RST.
sammy [17]

Given:

In rhombus RSTU, m\angle RUV=(10x-23)^\circ and m\angle TUV=(3x+19)^\circ.

To find:

The m\angle RST.

Solution:

We know that, diagonals of a rhombus are angle bisector. So,

m\angle RUV=m\angle TUV

(10x-23)^\circ=(3x+19)^\circ

10x-23=3x+19

Isolating variable terms, we get

10x-3x=23+19

7x=42

Divide both sides by 7.

x=\dfrac{42}{7}

x=6

Now,

m\angle RUV=(10x-23)^\circ

m\angle RUV=(10(6)-23)^\circ

m\angle RUV=(60-23)^\circ

m\angle RUV=37^\circ

And,

m\angle TUV=(3x+19)^\circ.

m\angle TUV=(3(6)+19)^\circ

m\angle TUV=(18+19)^\circ

m\angle TUV=37^\circ

Now,

m\angle RUT=m\angle RUV+m\angle TUV

m\angle RUT=37^\circ+37^\circ

m\angle RUT=74^\circ

We know that opposite angles of a rhombus are equal.

m\angle RST=m\angle RUT

m\angle RST=74^\circ

Therefore, the measure of angle RST is 74^\circ.

3 0
3 years ago
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 47.0 and 52.
Pavlova-9 [17]

Answer:

0.15 or 15%

Step-by-step explanation:

Since lengths are uniformly distributed, the probability that a class period runs between a two exact times is:

P(x_1\leq x \leq x_2)=\frac{x_2-x_1}{b-a}

In this case, a = 47.0 and b = 52.0 minutes.

The probability that a given class period runs between 50.25 and 51.0 minutes is:

P(50.25\leq x \leq 51.0)=\frac{51.0-50.25}{52-47} \\P(50.25\leq x \leq 51.0)=0.15=15\%

The probability is 0.15 or 15%.

7 0
3 years ago
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