I believe it’s B.) sorry if I’m wrong!!!!
Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
Answer:
4 Sliders 2 chicken wings
Step-by-step explanation:
4x300=1200 2x80=160
Answer:
-3,-5,-4,-1,1-1,1-1,,3,3-,-3,-4,5-,-8,9--,5,3
Step-by-step explanation:
Answer:
h = √(44) ft
Step-by-step explanation:
Just looked back and A is actually the area because the unit was ft².
Area of a right isosceles triangle is half the area of a square.
A = ½S²
in this case your side is h.
A = ½h²
2A = h²
√(2A) = h
√(2(22)) = h
√(44) = h
plug that in your calculator for the answer.
