12z - 3 ≥ 2z - 15
When you have to solve an equality like that, you need to put the variables apart (the numbers with letters) and the numbers apart.
So first, we need to reunite the variables, by subtracting "2z" from both sides of the equation:
12z - 3 ≥ 2z -15
12z - 2z - 3 ≥ 2z - 2z - 15
12z - 2z - 3 ≥ -15
10z - 3 ≥ 15
Then we add 3 to both sides:
10z - 3 + 3 ≥ -15 + 3
10z ≥ -12
Now divide both sides by 10
(10z)/10 ≥ -12/10
z ≥ -6/5
Now we need to write the answer as a mixed number.
-6/5 = -1.2
0.2 = 1/5
9
So -6/5 = -1 1/5.
So 12z - 3 ≥ 2z - 15 for Z ≥ -1 1/5
Hope this helps! :)
Answer:
L = 3W
Area, A = L x W = 108 in2
Substitute L = 3W into the area equation, you get
A = 3W x W = 108
3W2 = 108
W2 = 108 / 3 = 36
W = √36 = 6 in
Answer:
the graph rises to the left and falls to the right.
the answer is B
Step-by-step explanation:
Answer:
x<-2
Step-by-step explanation:
-5x+2/6 >2
-5x+2>12
-5x>12-2
-5x>10
-x>2
x<-2
P = perimeter
Perimeter of a rectangle = l + l + w + w
or P = 2l + 2w
You know:
P = 150 m
l = w + 5 [length is 5 m greater than the width]
P = 2l + 2w Plug in what you know
150 = 2(w + 5) + 2w Simplify, distribute/multiply 2 into (w + 5)
150 = 2w + 10 + 2w
150 = 4w + 10 Subtract 10 to both sides of the equation
140 = 4w Divide 4 on both sides
35 = w
PROOF l = w + 5 ---> l = 40
P = 2l + 2w
150 = 2(40) + 2(35)
150 = 80 + 70
150 = 150
