Answer:
V=5.333cubit unit
Step-by-step explanation:
this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1
The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z
The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below
V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:
Answer: I'm pretty sure I can help, just give me like 3 minutes..
-Angie
Swap x and y's positions
f(x) is another way of saying y, so basically tha initial function is y = 1-2x^3.
Change it up to x = 1-2y^3 and solve for y
X - 1 = - 2y^3
(X - 1)/-2 = y^3
So the cube root of ((x-1)/2) = y
Answer:
The circumference of the circle is 52π
Step-by-step explanation:
To solve this exercise we first have to calculate the radius of the circle, for this we will use the formula of area of a circle and we will clear the radius
a = area = 676π
r = radius
a = π * r²
we clear r
r = √(a/π)
now we replace the known values
r = √(676π/π)
r = √(676)
r = 26
now we use the formula to calculate the circumference of a circle
c = π * 2r
c = π * 2 * 26
c = 52π
The circumference of the circle is 52π
