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3 years ago

5 + 5 + ? Im Need To Know Please ; ]

Mathematics

2 answers:

RUDIKE [14]3 years ago

8 0

Answer:

10+x or 10+?

Step-by-step explanation:

('x' and '?' being a variable)

First you combine like terms. Here we have three terms, two of which we can combine. Positive five plus positive five is 10. But, we cannot forget about our remaining term, '+x' so we simply have '10' and '(plus)x' put them together and we achieve 10+x or 10+?

-BARSIC- [3]3 years ago

6 0

Answer:

5 plus 5 would equate to the variable of 10 :)

Step-by-step explanation:

5+5=10

1+1+1+1+1 + 1+1+1+1+1 = 10

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Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

What is the value of the expression 2^2 + 4^2 ÷ 2^2? 3 6 8 16

slamgirl [31]

The answer is 8 because you use the order of operations. So it would be 16 divided by 4, then you would do 4+4 which is 8

4 0

3 years ago

Now suppose instead that Jane withdraws $500 from her checking account and uses $300 of this money to pay her federal income tax

zysi [14]

Answer:

Step-by-step explanation:

a. Money held by individuals in savings accounts is part of the M2 money supply, but not part ofthe M1 money supply. Therefore, when Jane withdraws $500 cash from her savings account,the M1 money supply increases by $500. However, the M2 money supply does not changebecause the M1 money supply is included as part of the M2 money supply.b. Money held by banks and governments is not included as part of the money supply. Therefore,when Jane uses $300 to pay her income tax to the U.S. Treasury, that total of $300 is taken out ofboth the M1 and M2 money supplies. When Jane deposits the remaining cash ($80) into hersavings account, the M1 money supply is reduced by that amount, but it does not affect the M2money supply. Therefore, Jane's actions cause the M2 money supply to change by $300 (theamount used to pay her taxes) and the M1 money supply to change by $380 (the amount used topay her taxes plus the amount that was deposited into her savings account). Note that it does notmatter that Jane no longer has the $120 she used to pay for the gold clubs, as the funds remainsin someone else's checking account. So this amount is neither removed from the M1 moneysupply nor the M2 money supply.NumericResponseDifficulty: 03 HardLearning Objective: 1402 List anddescribe the components of the U.S.money supply.5000380300References

5 0

3 years ago

The integer between 42 and 140

Montano1993 [528]

It has 97 amounts.
43,44,45,46,47,48,49,50,
51,52,53,54,55,56,57,58,59,60
61,62,63,64,65,66,67,68,69,70 71,72,73,74,75,76,77,78,79,80
81,82,83,84,85,86,87,88,89,90
91,92,93,94,95,96,97,98,99,100
101,102,103,104,105,106,107,108,109,110
111,112,113,114,115,116,117,118,119,120
121,122,123,124,125,126,127,128,129,
130
131,132,133,134,135,136,137,138,139

Numbers between 42-140

6 0

2 years ago

6 Goes Into 2,000 How Many Times?

Leya [2.2K]

Answer:

333.333

Step-by-step explanation:

2000 devided by 6=333.333

8 0

2 years ago