We claim that the ratio of the areas is (3/2)^3=27/8, not just for these lengths, but also for every possible set of side-lengths x, y, and z.
To find the volume of the area of the original suitcase, multiply together x, y, and z to get xyz. The modified suitcase will have all these dimensions multiplied by 1 1/2, or 3/2, for a result of 3x/2*3y/x*3z/2=27xyz/8. The ratio is (27xyz/8)/(xyz)=27/8, as desired.
Note that we made no assumptions about the value of x, y, and z throughout the whole solution! Therefore, we can plug ANY side-lengths, including the problem's set (28, 16, 8) into this problem to achieve the same ratio.
Answer:
0.9 square units
Step-by-step explanation:
We assume you intend the vertices of the square to be (±√2, 0) and (0, ±√2). Then the diagonals of the square are 2√2 in length and its area is ...
(1/2)(2√2)² = 4
The radius of the inscribed circle is 1, so its area is ...
π·1² = π
and the area outside the circle, but inside the square is the difference of these areas:
area of interest = 4 - π ≈ 0.858407
area of interest ≈ 0.9
Answer:
B.-4+c
Step-by-step explanation:
multiple -1 with -C and 4
Answer:
pic1=56-28x
pic2=3cd+12c
pic3=s−t
pic4= the last answer
pic5= the third answer
Step-by-step explanation:
i did the math so just trust me
