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Travka [436]
4 years ago
15

On a map 0.75 inch represents 80 miles. Two cities that are 1025 miles apart will be how far apart on a map round to nearest ten

th of an inch
Mathematics
1 answer:
icang [17]4 years ago
4 0

The cities are 9.6 inches apart on map.

Step-by-step explanation:

Given,

80 miles in actual = 0.75 inch

1 mile = \frac{0.75}{80}\ inch

Distance between two cities = 1025 miles

1025 miles on map = 1025*\frac{0.75}{80}\\

1025\ miles\ on\ map=\frac{768.75}{80}\\\\1025\ miles\ on\ map=9.6\ inches

The cities are 9.6 inches apart on map.

Keywords: distance, multiplication

Learn more about distance at:

  • brainly.com/question/12613605
  • brainly.com/question/12700460

#LearnwithBrainly

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Figure J is the result of a transformation on Figure I. Which transformation would
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Answer:

Mirror across the y axis, then mirror across the x axis

Step-by-step explanation:

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3 years ago
Help Me With This Question Please! I'm Having A Hard Time Answering This Question! :(
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Answer:

15b square is the answer

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4 years ago
Tall Club International has a requirement that women must be at least 70 inches tall. Given that women have normally distributed
Marizza181 [45]

Answer:

0.0150 = 1.50% of women satisfy that height requirement.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 63.7, \sigma = 2.9

Find the percentage of women who satisfy that height requirement.

This is 1 subtracted by the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 63.7}{2.9}

Z = 2.17

Z = 2.17 has a pvalue of 0.9850

1 - 0.9850 = 0.0150

0.0150 = 1.50% of women who satisfy that height requirement.

8 0
3 years ago
In Jim's class, 5 times as many students take the bus as those who walk. A total of 24 students walk or take the bus. How many m
lana [24]
The answer is 16.  To solve this problem, it will look like this:
5 n + n = 24
So, 6(4) = 24. n=4
With this equation, you can see that 4 kids walk to school and 20 take the bus. Then you need to do 20 - 4 = 16. So 16 more kids take the bus than walk to school. 

Another way to look at it...
We know there are 5 times as many bus kids as there are walkers. 
walkers - n
bus kids - n+n+n+n+n
6n = 24 (the total number of students), which can translate to 6 x n = 24. We know that 6x4=24, so n=4. The number of kids that walk is 4. The number of kids on the bus is 20. So subtract the bus kids from the walking kids, and that leaves us the answer. 16 more students ride the bus than those who walk. I hope that helped.
3 0
3 years ago
Please helps, it’s evaluating. <br><br> Thank you.
-BARSIC- [3]

Answer:

the answer for the question is 5/28

7 0
3 years ago
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