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3 years ago

Usatp please help me

Mathematics

1 answer:

g100num [7]3 years ago

3 0

Answer:

A. 11

Step-by-step explanation:

11-3=9

The set does not include 9 because the sign is not underlined so 11 is not a solution.

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Solve the equation for x. a. -10 b. 1 c. 1/10 d. -1

Mashcka [7]

Answer:

2x - 5 = 5x - 2

3x = -3

x=-1

Step-by-step explanation:

Your welcome!!

Brainliest Please!!!

3 0

3 years ago

Read 2 more answers

Sara scored 8 goals this season. This is two less than a third of the goals she scored last season.

Charra [1.4K]

Answer:

30 goals last season

Step-by-step explanation:

Goals this season = 8

Goals this season = 1/3 of goals last season - 2

Let Goals scored last season = x

Therefore,

8 = 1/3x - 2

8 = x/3 - 2

8 + 2 = x / 3

10 = x / 3

x = 10 * 3

x = 30

Sara scored 30 goals last season

3 0

3 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

3 years ago

Please help extra points and mark brainlist

Montano1993 [528]

Answer:

the third one

Step-by-step explanation:

20.342 --> 0.3

0.3 × 100 = 30

8 0

3 years ago

The base area of a square-based prism is 25 ft squared. One of the lateral faces of the prism is 30 ft squared. What is the surf

telo118 [61]

Answer:

170 ft²

Step-by-step explanation:

Surface area = 4*lateral faces + 2*bases

A = 4*30 + 2*25 = 170 ft²

7 0

3 years ago