Answer:
A) ERROR
B) ∠C = 26°
Step-by-step explanation:
Houston, We have a problem!!! too much information
If we had a legit triangle, the law of sines would hold
19/sin138 = 8/sin20
28.395 = 23.390
as this is NOT an equality, the triangle does not exist as described.
IF it did, we'd get different results depending on which set we used
∠F = 180 - 138 - 20 = 22°
Law of sines
19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>
or
8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>
If we attempt to use Law of cosines
DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>
so really none is correct because we attempt to use trig calculations to a non-triangle.
12) AC² = 15² + 19² - 2(15)(19)cos120
AC = 29.51270...
29.51270 / sin120 = 15/sinC
C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>
1B
2C
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9514 1404 393
Answer:
x > -5
Step-by-step explanation:
(2/5)(x -1) < (3/5)(x +1) . . . . . given
2(x -1) < 3(x +1) . . . . . . . . . . .multiply by 5
2x -2 < 3x +3 . . . . . . . . . . . eliminate parentheses
-5 < x . . . . . . . . . . . . . . . . . . add -2x-3 to both sides
This matches the second answer choice: x > -5.
Answer:
B) angle B
Step-by-step explanation:
Since the question is telling you that both the triangles are essentially the same, you just have to look to see which letter of triangle ABC is in the same general place as triangle DEF.
In this case angle B is in the same general spot as angle E, so therefore B is your answer.
Hope this helps you :)
The sum of all angles in an octagon is given by
180*(n-2) >>>>>>>>>with n = 8
180*(8-2) = 1080 degrees
A + B = 1080 .......where
A is the <span>angle of an octagon which is twice that of the other seven angles
</span><span>
B equals the sum of the other seven angles
If we assume each angle of B is equal to each other, then
B = x+x+x+x+x+x+x = 7x
</span>
And A = 2x
The equation that results is
A + B = 2x +7x = 9x =1080
x = 120 degrees
2x = A = 240 degrees
