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drek231 [11]
4 years ago
5

Whats is 345 rounded to the nearest hundred​

Mathematics
1 answer:
Sholpan [36]4 years ago
6 0

300.

Since it is below 350 you round down to 300, if it was above you round up to 400.

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A ski gondola cabin can safely carry x number of people. there are already 2 over 3x people in the cabin another 15 are allowed
4vir4ik [10]
You can have 24 ppl on the ski gondola


5 0
3 years ago
Helpppppp i give you 98 points !!!!!!!!!!!!Using the distributive property to find the product (y−4x)(y2+4y+16) results in a pol
Marina CMI [18]

Answer:

16

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

y(y² + 4y + 16) - 4x(y² + 4y + 16) ← distribute both parenthesis

= y³ + 4y² + 16y - 4xy² - 16xy - 64x

Compare - axy to - 16xy ⇒ a = 16

4 0
3 years ago
Read 2 more answers
(NEED HELP WILL MARK BRAINLIEST)
Monica [59]

Answer:

D

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Find x.______________a0
velikii [3]

Answer:

x=4

Step-by-step explanation:

Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.

Let altitude = y; solve for y:

\frac{2}{y}=\frac{y}{6}

y^2=12

y=\sqrt{12}

y=2\sqrt{3}

Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).

a^2+b^2=c^2

2^2+(2\sqrt{3})^2=c^2

4+12=c^2

c^2=16

c=4

Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

x=4

4 0
3 years ago
Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9
natulia [17]
Parameterize C by

\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle

where 0\le t\le\pi. Then the line integral is

\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt
=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt
=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt

Take u=\cos t, then

=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du
=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du
=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du
=54
6 0
4 years ago
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