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Leya [2.2K]
3 years ago
11

When Ryan is serving at a restaurant, there is a 0. 75 probability that each party will order drinks with their meal. During one

hour, Ryan served 6 parties. Assuming bc that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
3 0

Answer:

0.82

Step-by-step explanation:

We are given that

Total number of parties=n=6

The probability that each party will order drinks with their meal,q=0.75

The probability that party will not order drink with their meal=p=1-0.75=0.25

We have to find the probability that at least one party will not order drinks with their meal

Binomial probability distribution

P(x=r)=nC_rq^{n-r}p^r

Using  the formula

P(x=0)=6C_0(0.75)^6

P(x=0)=\frac{6!}{6!}(0.75)^6

Using formula;nC_r=\frac{n!}{r!(n-r)!}

P(x=0)=(0.75)^6

P(x\geq 1)=1-P(x=0)

P(x\geq 1)=1-(0.75)^6

P(x\geq 1)=0.82

Hence, the probability that at least one party will not order drinks=0.82

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Answer:

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Step-by-step explanation:

Options:

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From the given options (a) to (d), option (a) is true.

This is so, because.

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V_2 = \pi r^2h

In other words:

V_1 = \frac{1}{3}V_2

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3 years ago
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Vlada [557]

a. Notice that

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1/(2*3) = 1/6 = 1/2 - 1/3

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