Question

When Ryan is serving at a restaurant, there is a 0. 75 probability that each party will order drinks with their meal. During one hour, Ryan served 6 parties. Assuming bc that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

Answer 1

Answer:

0.82

Step-by-step explanation:

We are given that

Total number of parties=n=6

The probability that each party will order drinks with their meal,q=0.75

The probability that party will not order drink with their meal=p=1-0.75=0.25

We have to find the probability that at least one party will not order drinks with their meal

Binomial probability distribution

$P(x=r)=nC_rq^{n-r}p^r$

Using  the formula

$P(x=0)=6C_0(0.75)^6$

$P(x=0)=\frac{6!}{6!}(0.75)^6$

Using formula;$nC_r=\frac{n!}{r!(n-r)!}$

$P(x=0)=(0.75)^6$

$P(x\geq 1)=1-P(x=0)$

$P(x\geq 1)=1-(0.75)^6$

$P(x\geq 1)=0.82$

Hence, the probability that at least one party will not order drinks=0.82