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3 years ago

25 ≥ 5u u = 5 True of false ( show work )

Mathematics

1 answer:

iris [78.8K]3 years ago

6 0

Answer:

true

Step-by-step explanation:

plug in u. u=e

25>= 5x5

25>=25

true

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The following circle graph represents first-quarter absences of Washington Middle School students. If 96 students had two or mor

UkoKoshka [18]

How many students had 3 or more absences? Add together {45%, 21%, 23%} and subtract that sum from 100%: 11%.

How many students had two or more absences? Add together this 11% and 21%: 32% had two or more absences. Let the total number of students be n. Then 32% of these n students add up to 96 students. Thus, 0.32n = 96, and n= 300.

How many students had one absence? The chart shows that that is 45%, and we know that there are 300 students total.

Thus, the number of students who had one absence was 0.45(300) = 135.

4 0

3 years ago

Read 2 more answers

A gym teacher has 250 to spend on volleyball, she buys for volleyball nets that cost $28 volleyballs are $7 each.how many volley

MaRussiya [10]

The gym teacher has $250 to spend on volleyball equipment. She buys 4 volleyball nets for $28 each. Volleyballs cost $7 each. How many volley balls can she buy

Answer:

she can buy maximum of 19 balls.

Step-by-step explanation:

Let the number of volleyballs be x

we know that

$\text{(The cost of each volleyball net} \times \text{number of volleyball net)}+\text{(the cost of each volleyball} \times \text{number of volleyballs)}\leq \ 250$

so substituting the values,

$28(4) + 7x \leq 250$

$112 + 7x \leq 250$

$7x \leq 250 - 112$

$7x \leq 138$

$x \leq \frac{138}{7}$

$x \leq 19.7$

3 0

3 years ago

Find a formula for the least squares solution of ax=b when the columns of a are orthonormal1 .

neonofarm [45]

Let $\mathbf A$ be a rectangular $m\times n$ matrix with column vectors $\mathbf a_1,\ldots,\mathbf a_n$ , i.e.

$\mathbf A=\begin{bmatrix}\mathbf a_1&\cdots&\mathbf a_n\end{bmatrix}$

Then we have

$\mathbf A^\top=\begin{bmatrix}\mathbf a_1&\cdots&\mathbf a_n\end{bmatrix}^\top$

and the product of the two is

$\mathbf A^\top\mathbf A=\begin{bmatrix}\mathbf a_1\cdot\mathbf a_1&\mathbf a_1\cdot\mathbf a_2&\cdots&\mathbf a_1\cdot\mathbf a_n\\\mathbf a_2\cdot\mathbf a_1&\mathbf a_2\cdot\mathbf a_2&\cdots&\mathbf a_2\cdot\mathbf a_n\\\vdots&\vdots&\ddots&\vdots\\\mathbf a_n\cdot\mathbf a_1&\mathbf a_n\cdot\mathbf a_2&\cdots&\mathbf a_n\cdot\mathbf a_n\end{bmatrix}$

Because the columns of $\mathbf A$ are orthonormal, we have

$\mathbf a_i\cdot\mathbf a_j=\begin{cases}1&\text{for }i=j\\0&\text{for }i\neq j\end{cases}$

which means $\mathbf A^\top\mathbf A$ reduces to an $n\times n$ matrix with ones along the diagonal and zero everywhere else, i.e.

$\mathbf A^\top\mathbf A=\begin{bmatrix}1&0&\cdots&0\\0&1&\cdots&0\\\vdots&\vdots&\ddots&\vdots\\0&0&\cdots&1\end{bmatrix}=\mathbf I_n$

where $\mathbf I$ denotes the identity matrix. This means the solution to $\mathbf{Ax}=\mathbf b$ is given by

$\mathbf A^\top(\mathbf{Ax})=\mathbf A^\top\mathbf b\implies(\underbrace{\mathbf A^\top\mathbf A}_{\mathbf I})\mathbf x=\mathbf A^\top\mathbf b\implies\mathbf x=\mathbf A^\top\mathbf b$

6 0

3 years ago

!!HELP!! algebra two!! multiply and combine like terms to write as the sum of difference of monomials!! a-i !!!explanation, if p

vazorg [7]

Answer:

a. 10a + 8a²

c. 12z + 3z²

e. -20 + x + x²

g. -64 + 9z⁴

i. y¹⁰⁰¹ + 8y¹³²⁰⁰

Step-by-step explanation:

According to the Six Exponential Rules, whenever you divide terms, you subtract the exponents, and of course whenever you multiply terms, you add the exponents.

a. The variables have an invisible degree term of 1, so when multiplied, you get 8a².

c. ⅛ of 24 and 96 means dividing both numbers by its multiplicative inverse, which is 8: ⅛[24] → 24 ÷ 8; 3; ⅛[96] → 96 ÷ 8; 12. Then of course, you still have to follow the exponential procedure.

e. This is just like the Quadratic Equation, y = Ax² + Bx + C. All you have to do is do what I like to call FOIL:

F - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outermost] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Innermost] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

Doing this will give you the above answer.

g. See explanation letter e.

i. Now, as I mentioned before, when you multiply terms, you add the exponents. In addition, that decimal in the far right corner, is equivalent to ⅛, and ⅛ of 8 is 1, so we know that 1 is our INVISIBLE coefficient next to the y, then you just add 1 to 1000 in the exponents because of the invisible degree of 1.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**I have a video that talks about the Six Exponential Rules. It is titled "Six Exponential Procedures". Go check out the channel to watch it and gain more assistance.

4 0

3 years ago

Which of the following equations passes through the point (0, -6) and is parallel to

LiRa [457]

Step-by-step explanation:

Y = 3 X-6

... . .... ... ...

3 0

3 years ago