Answer: g(h(3)) = 59
Step-by-step explanation:
Well if its x^3 I assume it is because you wrote other coefficients before the variable.
2(3) - 2 = 6-2 = 4
So 4 is the x input for h(x)
4^3 -5 = 64-5 = 59
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
Answer:
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I don't know the answear sorry
Answer:
w+d≥14
Step-by-step explanation:
Here is the full question
Morgan is working two summer jobs, washing cars and walking dogs. She must work no less than 14 hours altogether between both jobs in a given week. Write an inequality that would represent the possible values for the number of hours washing cars, w, and the number of hours walking dogs, d, that Morgan can work in a given week.
Morgan must not work less than 14 hours. This means that the least amount of hours she can work would be 14 hours. This would be represented by the greater to or equal to sign (≥)
So the time she would spend working = w+d≥14
2
The length is 8 and the width is 4
P = L + L + W + W
P = 8 + 8 + 4 + 4
P = 16 + 4 + 4
P = 16 + 8
P = 24
