Given data:
● Angular velocity of the turntable ω = 33 rev/min
Therefore,
ω = 33 rev/min
ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s
● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m
● μs = the coefficient of static friction
Section a:
The seed is undergoes circular motion and it is been effected by centripetal acceleration.
ac = rω^2
ac = 0.078 × 3.45^2
ac = 0.9284 m/s^2
Therefore,
the centripetal acceleration of the seed is 9.274 m/s^2
Section b:
If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.
Centripetal Force = Frictional Force
mrω^2 = μsmg
μs = rω^2 /g
μs = 0.078 × 3.45^2
------------
9.81
μs = 0.09464
Thus,
the coefficient of static friction is 0.09464.
"<span>No, because group C should be the control group" is the one among the choices that are given in the question that correctly answers the question. The correct option among all the options that are given in the question is the last option or option "D". I hope the answer has come to your help.</span>
Answer:
1. Hybrids
2. H-o-m-o-z-y-g-o-u-s
Explanation:
1. The offspring of an F1 generation obtained by crossing true-breeding green seeded pea plant and true-breeding yellow seeded pea plant are called hybrids.
2. An organism with identical alleles for a trait is said to be h-o-m-o-z-y-g-o-u-s for that trait.
The charge is negative. The charge should be negative because there is one more electron (-) than there is protons (+)
I hope that answers ur question fully and helps...lmk if its right or not. :)
