39=9x+7-3x+20

Subtract 27 from each side

12=6x
2=x

Now plug in 2 for x to find AB and BC

9x+7= AB
9(2)+7=AB
18+7= AB
25= AB

-3x+20= BC
-3(2)+20= BC
-6+20= BC
14= BC

3 0

2 years ago

Changle. Show all work. Round each length to the nearest tenth and each angle to the

Sedaia [141]

Answer:

Part 1) $BC=12.2\ units$

Part 2) $m\angle A=55^o$

Part 3) $m\angle C=35^o$

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=7^2+10^2$

$AC^2=149\\AC=12.2\ units$

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

$tan(A)=\frac{BC}{AB}$ ----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{10}{7}$

using a calculator

$m\angle A=tan^{-1}(\frac{10}{7})=55^o$

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

$m\angle A+m\angle C=90^o$ ----> by complementary angles

substitute the given value

$55^o+m\angle C=90^o$

$m\angle C=90^o-55^o=35^o$

8 0

2 years ago

A kangaroo hops 2 kilometers in 3 minutes. At this rate:

nikitadnepr [17]

It takes 7 minutes and 30 seconds to travel 5 kilometers because first you divide 3 and 2 to figure out how many minutes is 1 kilometer and you get 1.5 then you multiply 5 and 1.5 to get the minutes of 5 kilometers. Also the kangaroo travels 1.3 kilometers in 2 minutes

3 0

2 years ago

Please help with this algebra problem!! thanks

saw5 [17]

5.7t < 420 divide both sides by 5.7

5.7 5.7

t < 73.68

5 0

3 years ago

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