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ycow [4]
2 years ago
15

A) C = √19-8√3 b) D = √5-2√6 c) √(√2+1)^2 - √(√2-5)^2 d) E = √(√7+√13) - √(7-13)

Mathematics
1 answer:
lord [1]2 years ago
7 0
D be a explanation

Explain
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The graph of g(x) is f(x) translated to the left 8 units and up 2 units. What is the function rule for g(x) given f(x) = x²?
NNADVOKAT [17]
Translation of a function y = h(x) to the right/left is given by y = h(x + a)  for translation to the left by 'a' units and y = h(x - a) for translation to the right by 'a' units

Translation of a function y = h(x) up/down the y-axis is given by y = h(x) + a for translation 'a' unit up and y = h(x) - a for translation 'a' unit down

So, translating f(x) = x² eight units right and two units up gives:

g(x) = (x-8)² + 2
7 0
3 years ago
Which segment is half the diameter?<br> A. CD<br> B.CB<br> C.CB<br> D.CA
larisa [96]

Answer: D

Step-by-step explanation:

I am guessing but sorry if I am wrong

3 0
3 years ago
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After 3 minutes, a submarine had descended to −320 feet. After 8 minutes, the submarine had descended to −420 feet. Assuming a l
Alenkasestr [34]

Answer:

  d(t) = -20t -260

Step-by-step explanation:

We are given two points ...

  (t, d) = (3, -320) and (8, -420)

The 2-point form of the equation of a line can be useful when 2 points are given.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Substituting the given points, we have ...

  d(t) = (-420 -(-320))/(8 -3)(t -3) -320

  d(t) = -20(t -3) -320

  d(t) = -20t -260

5 0
3 years ago
5.2.14. For the negative binomial pdf p (k; p, r) = k+r−1 (1 − p)kpr, find the maximum likelihood k estimator for p if r is know
Volgvan

Answer:

\hat p = \frac{r}{\bar x +r}

Step-by-step explanation:

A negative binomial random variable "is the number X of repeated trials to produce r successes in a negative binomial experiment. The probability distribution of a negative binomial random variable is called a negative binomial distribution, this distribution is known as the Pascal distribution".

And the probability mass function is given by:

P(X=x) = (x+r-1 C k)p^r (1-p)^{x}

Where r represent the number successes after the k failures and p is the probability of a success on any given trial.

Solution to the problem

For this case the likehoof function is given by:

L(\theta , x_i) = \prod_{i=1}^n f(\theta ,x_i)

If we replace the mass function we got:

L(p, x_i) = \prod_{i=1}^n (x_i +r-1 C k) p^r (1-p)^{x_i}

When we take the derivate of the likehood function we got:

l(p,x_i) = \sum_{i=1}^n [log (x_i +r-1 C k) + r log(p) + x_i log(1-p)]

And in order to estimate the likehood estimator for p we need to take the derivate from the last expression and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\frac{x_i}{1-p}

And we can separete the sum and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}

Now we need to find the critical point setting equal to zero this derivate and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}=0

\sum_{i=1}^n \frac{r}{p} =\sum_{i=1}^n \frac{x_i}{1-p}

For the left and right part of the expression we just have this using the properties for a sum and taking in count that p is a fixed value:

\frac{nr}{p}= \frac{\sum_{i=1}^n x_i}{1-p}

Now we need to solve the value of \hat p from the last equation like this:

nr(1-p) = p \sum_{i=1}^n x_i

nr -nrp =p \sum_{i=1}^n x_i

p \sum_{i=1}^n x_i +nrp = nr

p[\sum_{i=1}^n x_i +nr]= nr

And if we solve for \hat p we got:

\hat p = \frac{nr}{\sum_{i=1}^n x_i +nr}

And if we divide numerator and denominator by n we got:

\hat p = \frac{r}{\bar x +r}

Since \bar x = \frac{\sum_{i=1}^n x_i}{n}

4 0
3 years ago
Wiley is making monthly payments of $88.00 to pay off a loan that he took out to buy a fence, but he wants to pay off his loan f
bekas [8.4K]
Making larger monthly payments than required will pay off a loan faster.  Thus, the answer is A.
6 0
3 years ago
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