Slope-intercept form is y = mx + b, so to turn that equation into slope-intercept you'll need to get y alone
4x - 8y = 8 --- subtract 4x
-8y = 8 - 4x --- divide by -8
y = -1 + (1/2)x --- reorder to match "mx + b"
y = (1/2)x - 1
in y = mx + b, "m" is the slope and "b" is the y-intercept. so for part B, your slope is (1/2) and your y-intercept is (-1). take the sign with you.
for part C, you'll need to know point-slope form: (y - y1) = m(x - x1)
you'll also need to be aware that "perpendicular" lines have a slope that is the opposite reciprocal of the original line.
the original slope is (1/2). change the sign to negative and form a reciprocal: your new slope is -2. plug that into your point-slope form
(y - y1) = m(x - x1)
(y - y1) = (-2)(x - x1)
and lastly, plug in your given point: (1, 2)
y - 2 = (-2)(x - 1)
so, just to look a little neater without all of the work:
A) y = (1/2)x - 1
B) m = (1/2), b = -1
C) y - 2 = (-2)(x - 1)
Answer:
2.7
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
see image
Answer:
200 rev.
Step-by-step explanation:
Answer:
<h2>The obtuse angle is 120°.</h2><h2>The acute angle is 60°.</h2>
Step-by-step explanation:
This problem is about two crossing line, when that happens, we have 4 angles, two acute and two obtuse, where adjacent angles are supplementary and vertical angles are equal.
We can form the expression
Where 
is an acute angle and 
is an obtuse angle.}
Using all the given information, we have
Solving for , we have
Therefore, the obtuse angle is 120°, which means the acute angle is 60°, because they are supplementary angles, as we said befor.
