The final equation is:

Further explanation:
The general form of equation of a line in slope-intercept form is:

Here m is the slope
Given
m=1
(x,y) = (-7,-4)

To find the value of b, we have to put the point in the equation

The final equation is:

Keywords: Slope-intercept form, equation of line
Learn more about slope-intercept form at:
#LearnwithBrainly
S = 10 + r
s + r = 100
Adding equations,
2s +r = 110 + r
2s = 110
s = 55
r = 45
Given the next quadratic function:

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:
Answer:
yes
Step-by-step explanation:
y(x) is even or odd according as y(−x)=±y(x) . Here, #y(-x)=-(-x)^3=-(-x^3)=x^3=-y(x). So, y is an odd function of x.
Answer:
see explanation
Step-by-step explanation:
Given A = 3x² + 2y + 2 and B = 6x² - 8y + 1 , then
A + B
= 3x² + 2y + 2 + 6x² - 8y + 1 ← collect like terms
= 9x² - 6y + 3
-------------------------------
A - B
= 3x² + 2y + 2 - (6x² - 8y + 1) ← distribute parenthesis by - 1
= 3x² + 2y + 2 - 6x² + 8y - 1 ← collect like terms
= - 3x² + 10y + 1