What is the answer to this problem (X+3)(x-1)

Mathematics

1 answer:

uysha [10]2 years ago

3 0

you need to distribute your first function (x+3) to the second function (x-1)

x^2 -1x+3x-3 then you need to combine the like values to get your final answer

x^2 +2x-3

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Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

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For the perimeters to be the same

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The value of x that makes the perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

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