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3 years ago

Find three consecutive even integers have a sum of 48.

Mathematics

2 answers:

yan [13]3 years ago

7 0

Answer:

14, 16, 18

Step-by-step explanation:

x + (x+2) + (x+4)= 48

3x + 6 = 48

3x = 42

x = 14

x+2 = 16

x+4 = 18

yanalaym [24]3 years ago

7 0

Answer:

14, 16 and 18

Step-by-step explanation:

let the numbers be defined as x, x+2 and x+4.

Now,

x+x+2+x+4=48

3x+6=48

subtract 6 from both sides

3x=48-6

3x=42

divide both sides by 3

x=42/3=14

therefore

x=14

x+2=16

X+4=18

Hence, the numbers are 14, 16 and 18.

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3 years ago

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$