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castortr0y [4]
4 years ago
13

Find three consecutive even integers have a sum of 48.

Mathematics
2 answers:
yan [13]4 years ago
7 0

Answer:

14, 16, 18

Step-by-step explanation:

x + (x+2) + (x+4)= 48

3x + 6 = 48

3x = 42

x = 14

x+2 = 16

x+4 = 18

yanalaym [24]4 years ago
7 0

Answer:

14, 16 and 18

Step-by-step explanation:

let the numbers be defined as x, x+2 and x+4.

Now,

x+x+2+x+4=48

3x+6=48

subtract 6 from both sides

3x=48-6

3x=42

divide both sides by 3

x=42/3=14

therefore

x=14

x+2=16

X+4=18

Hence, the numbers are 14, 16 and 18.

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Solve the equation y. 6=2(y+2)
atroni [7]

Answer:

y = 1

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    6-(2*(y+2))=0

Step by step solution :

Equation at the end of step  1  :

 6 -  2 • (y + 2)  = 0

Pulling out like terms :

3.1     Pull out like factors :

  2 - 2y  =   -2 • (y - 1)

Equation at the end of step  3  :

 -2 • (y - 1)  = 0

Equations which are never true :

4.1      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2      Solve  :    y-1 = 0

Add  1  to both sides of the equation :

                     y = 1

One solution was found :

                  y = 1

Processing ends successfully

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Please help im being timed <br><br> Inverse of f(x)=15x+4
rusak2 [61]

Answer:

f^{-1}(x) =

Step-by-step explanation:

let y = f(x), then rearrange making x the subject

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5y - 20 = x

Change y back into terms of x with x = f^{-1} (x) , then

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