Answer:
Yes.
Step-by-step explanation:
Answer:
g(-1 )=-1 and g(2)+g(1)=7
Step-by-step explanation:
If g(x) = x^3+x^2-x-2 find g(-1)
if we find g(-1)
we substitute all the x's in the function with -1
-1^3+-1^2-(-1)-2
-1^3 = -1
-1^2 = 1
-1+1+1-2
(two minuses make a plus)
-1+1 = 0
0+1 = 1
1-2 = -1
if x=-1, g(-1) is -1
g(2)+g(1)
substitute the x's in the function with 2 and 1 and add your results
2^3+2^2-2-2
2^3 = 8, 2^2 = 4
8+4-2-2
8+4= 12, 12-2 = 10, 10-2 = 8
g(2)=8
g(1) now
1^3 + 1^2-1-2
1^3=1, 1^2 = 1
1+1-1-2
1+1 = 2, 2-1 = 1, 1-2 = -1
g(3) = -1
g(2) (which equals 8) + g(3) (which equals -1) =
8+(-1) = 7
g(2)+g(3)=7
The answer would be an odd number, 111.
Answer:
b = √(c^2 - a²)
Step-by-step explanation:
Start with the given c = √a^2 + b^2. Squaring both sides, we get:
c² = a² + b².
We want to iosolate b² and then b.
So: subtract a² from both sides, resulting in:
c² - a² = b²
Taking the square root of both sides, we get:
√b² = √(c² - a²)
and so:
b = √(c^2 - a²)
To solve for x, put all of the angle measurements on one side of an equation and set it equal to 360, because the sum of any exterior angles is 360 degrees. hope this helped!
