solution:
Consider the differential equation,
7ty + (1+t2)1/2y1 = 0
Rewrite the DE as,
(1+t2)1/2dy = - 7ty
dy/y = -7t/√1+t2 dt
in y = -7(1+t2) + c
y = ce-7(1+t2)
given,
y(0) = 1 => ce-7 = -1 => c = e7
ᴪ (t,y) = y -ce ᴪ(0,1)(1+t2)
Answer: y = -1/3x -5 (4th option is correct)
Step-by-step explanation:
- The slope of a perpendicular line is opposite reciprocal --> -1/3
- Find b.
- -4 = -3(-1/3) + b
- -4 = 1 +b
- -5 = b
I know that the answer for number 10 is the first option
It equals to:
(3(a+h)^2 - 3a^2) / h = 3(2ah+h^2) / h = 6a + 3h
