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Xelga [282]
3 years ago
8

Simplify. 4−16÷4+42 −16 13 15 16PLEASE HELP

Mathematics
2 answers:
dolphi86 [110]3 years ago
7 0

Its 16 I took the test.

jok3333 [9.3K]3 years ago
3 0
PEMDAS. 16/4 = 4. 4+42 = 46. 46-4 = 42. Answer is 42!
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What fraction is equal to 6? 1/6, 6/6, 6/1, 6/10, or 6/60
inna [77]

Answer:

6/10

Step-by-step explanation:

7 0
3 years ago
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Kiteretsuki builds a robot to help him paint a fence. The robot has a paint roller of width 1 foot, that works like a ball-point
balandron [24]

Answer:

72 inches

Step-by-step explanation:

Due to the programming error, the robot first moves to the right and then to the left. The second time it moves to the right, it increases its distance by 1 foot to the right and then turns back and moves to the left, reaching the starting position again.

The patterns is as follows:

move 1: moves to the right by 1 foot.

moves 2: moves to the left.

moves 3: moves to the right by 2 feet.

moves 4: moves to the left

moves 5: moves to the right by 3 feet.d

moves 6: moves to the left

moves 7: moves to the right by 4 feet.

moves 8: moves to the left

moves 9: moves to the right by 5 feet.

moves 10: moves to the left

moves 11: moves to the right by 6 feet.

We see that in the end, the robot has managed to only move 6 ft. Since 1 ft = 12 inches, 6 ft = 6* 12 = 72 ft.

So, the robot has painted 72 inches of the fence before Kiteretsuki returns.

8 0
3 years ago
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Alexeev081 [22]
1)
evaluate when x = 6
5 + x
so when x = 6 then 5 + 6 = 11
answer

11

2)
2/6
in lowest term = 1/3 (divide top and bottom by 2)

3)
evaluate when x = 1
8 + x
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answer: 9

4)
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5 0
3 years ago
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What scale factor was applied to the first rectangle to get the resulting image?
Katena32 [7]

the scale factor is .25

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3 0
2 years ago
An object is thrown upward at a speed of 96 feet per second by a machine from a height of 14 feet off the ground. The height of
liberstina [14]

Answer:

8t^2 -48 t -7=0

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

a= 8, b =-48, c = -7 and replacing we got:

t_1 = \frac{48 - \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = -0.1425

t_2 = \frac{48 + \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = 6.142

And since the time cannot be negative the correct answer for this cae would be t = 6.142 s

Step-by-step explanation:

If the question is: When will the object hit the ground at when the time is how many seconds?

We have the function for the heigth given by:

h(t) = -16t^2 +96 t +14

And we want to find the time where h(t) =0 so we can set like this the condition:

0 =-16t^2 +96 t +14

And we can rewrite the expression like this:

16t^2 -96 t -14 =0

We can divide both sides of the equation by 2 and we got:

8t^2 -48 t -7=0

And we can use the quadratic equation to solve for t like this:

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

a= 8, b =-48, c = -7 and replacing we got:

t_1 = \frac{48 - \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = -0.1425

t_2 = \frac{48 + \sqrt{(-48)^2 -4(8)(-7)}}{2*8} = 6.142

And since the time cannot be negative the correct answer for this cae would be t = 6.142 s

7 0
3 years ago
Read 2 more answers
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