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3 years ago

Is an estimate of 8 as the difference between 4.7 and -3.3 reasonable? Explain.

1 answer:

3 0

$\bf \underset{\textit{\large 3.3 + 4.7 = 8}}{\stackrel{\textit{3.3 units}}{\boxed{-3.3}\rule[0.35em]{10em}{0.25pt}}0\stackrel{\textit{4.7 units}}{\rule[0.35em]{17em}{0.25pt}\boxed{4.7}}}$

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What is the sum of complex numbers 2+3i and 4+8i, where i= square root -1

bearhunter [10]

Answer:

6+11i

Step-by-step explanation:

2+3i + 4+8i

Add the real parts

2+4 = 6

And the imaginary parts

3i+8i = 11i

The complex number is the real plus the imaginary

6+11i

3 0

3 years ago

When is making a strawberry cake for her brother's birthday the cake Pan is right rectangular prism 20 cm wide by 28 cm long whe

Anna [14]

Answer:

3 2/7 or 23/7 cms

Step-by-step explanation:

So we know the volume of a prism = L * W * H

And with the given info we know = L=28 and W=20 and Vol=1840

we solve for H and we get 23/7

8 0

4 years ago

Trisha drew a pair of line segments starting from a vertex. Which of these statements best compares the pair of line segments wi

Ksju [112]

The <em>correct answer</em> is:

C) Line segments have two endpoints and a vertex is a common endpoint where two line segments meet.

Explanation:

A line segment is defined as a portion of a line that has two endpoints.

A vertex is defined as the common endpoint of two or more rays or line segments.

This makes C the correct option.

6 0

3 years ago

Read 2 more answers

Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n

Nady [450]

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

The maclaurin series for f(x) is defined by the following formula:

$f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}$ --------------(1)

Where $f^{i}$ is the i - th derivative of the function

If f(x) = $e^{-6x}$ , then the formula of the i - th derivative of the function is:

$f^{i} =(-6)^{i} .e^{-6x}$ ----------------------(2)

Then,

$f^{i}(0) = (-6)^{i}$

Lastly, the equation of the trascendental function by Maclaurin series is: $f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i} }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ ---------------(3)

Hence,

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

Find out more information about maclaurin series here

brainly.com/question/24179531

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4 0

1 year ago

Use a system of linear equations with two variables and two equations to solve.

Pachacha [2.7K]

Answer:

passed: 164

failed: 41

Step-by-step explanation:

Let the failed students be x, then the passed students will be 4x.

x + 4x = 205

x = 205/5 = 41

4x = 4*41 = 164

7 0

3 years ago