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3 years ago

Drag each equation to show if it could be a correct first step to solving the equation

Mathematics

1 answer:

mote1985 [20]3 years ago

5 0

Answer:

9(8 + 2 = 10) = 90

9 times 10 = 90

x = 8

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garri49 [273]

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3 years ago

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Is trapezoid ABDC the result of a dilation of trapezoid MNPQ by a scale factor of ? Why or why not?

Nady [450]

Answer:

No, because AB is 2/5 the length MN but CD is 1/3 the length QP.

Step-by-step explanation:

Comparing the corresponding sides, the length of AB is 4. The length of MN is 10. This makes their ratio 4/10 = 2/5.

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Sally finds a coin with a radius of 1.5 centimeters and a thickness of 0.25 cm. It has a measured mass of 18.54 grams. How can S

mote1985 [20]

Answer:

Silver

Step-by-step explanation:

Find the volume of the coin

<u>Volume of a cylinder</u>

$\textsf{V}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}$

Given:

r = 1.5 cm
h = 0.25 cm

Substituting given values into the formula to find the volume:

$\sf \implies V=\pi (1.5)^2(0.25)$

$\sf \implies V=0.5625 \pi \:cm^3$

Find the density of the coin given it has a measured mass of 18.54 g

<u>Density formula</u>

$\sf \rho=\dfrac{m}{V}$

where:

$\rho$ = density
m = mass
V = volume

Given:

m = 18.54 g
$\sf V=0.5625 \pi \:cm^3$

Substituting given values into the density formula:

$\implies \sf \rho=\dfrac{18.54}{0.5625 \pi}$

$\implies \sf \rho=10.49149385\:g\:cm^{-3}$

Given:

$\textsf{Density of Lead}=\sf 11.3\:g\:cm^{-3}$

$\textsf{Density of Silver}=\sf 10.49\:g\:cm^{-3}$

Therefore, as $\sf \rho=10.49\:g\:cm^{-3}$ the coin is made from silver.

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2 years ago