Ask question

Ask question

All categories

2 years ago

5

Solve for x in the diagram below

1 answer:

Lapatulllka [165]2 years ago

5 0

Answer:

26.67

Step-by-step explanation:

You might be interested in

Miranda and Luci went out to dinner. They each ordered the same sandwich and drink, and they left the same amount of tip. Howeve

dlinn [17]

Use p for the price of the sandwich and drink.
(p+ 2.95 x.15) + (p x .20)

(I JUST GUESSED. IM VERY DUMB, SO DO NOT TRUST THIS ANSWER.

8 0

3 years ago

I need help please . <br> What does y=?

vazorg [7]

Answer:

null

Step-by-step explanation:

i cant see the question very well

7 0

3 years ago

Write and solve a system of linear equations: The larger of two numbers is 18 more than 5 times

Kryger [21]

Answer:

8 and - 2

Step-by-step explanation:

let x be the larger number and y the smaller , then

x = 5y + 18 → (1)

3x + 4y = 16 → (2)

substitute x = 5y + 18 into (2)

3(5y + 18) + 4y = 16 ← distribute parenthesis and simplify left side

15y + 54 + 4y = 16

19y + 54 = 16 ( subtract 54 from both sides )

19y = - 38 ( divide both sides by - 19 )

y = - 2

substitute y = - 2 into (1)

x = 5(- 2) + 18 = - 10 + 18 = 8

then larger number is 8 and smaller is - 2

8 0

2 years ago

The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

I need help what is 7h+1−h+4?

zloy xaker [14]

Answer:

6h+5

Step-by-step explanation:

7h-h=6h

1+4=5

Hope this helps :)

3 0

3 years ago

Read 2 more answers