Hi! I'm happy to help!
Our total line is JL (4x), and it is split into two parts: JK, and KL. We have our values, and we know that JK+KL=JL, so we can substitute our values and solve for x:
4x=(2x+3)+(x)
4x=3x+3
To solve for x, we have to isolate it on one side of the equation.
First, let's subtract 3x from both sides so that we can isolate x:
4x=3x+3
-3x -3x
x=3
<u>So, our x=3, which means that KL=3.</u>
I hope this was helpful, keep learning! :D
When n = 1, 2(1) + 1 = 3
When n = 2, 2(2) + 1 = 5
When n = 3, 2(3) + 1 = 7
When n = 4, 2(4) + 1 = 9
When n = 5, 2(5) + 1 = 11
Sum = 3 + 5 + 7 + 9 + 11 = 35
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Answer: 35
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Answer:
is sometimes positive and sometimes negative.
Step-by-step explanation:
Take 
Take 
Hence 
for 
and 
for 
So is sometimes positive and sometimes negative in the interval.
Sure
i will help with the page if i can do it…
The slope of the line given its equation is calculated through, m = -A / B. The slope of the given line is 4/3. The line perpendicular to it has the slope of -3/4. The slope-point form of the equation is,
y - y1 = m(x - x1)
where m is the slope and x1 and y1 the abscissa and ordinate of the point, respectively.
Substituting the values above,
y --2 = (-3/4)(x - 3)
Simplifying the equation gives 3x + 4y = 1.
