What is the slope of this graph?

Mathematics

1 answer:

Rufina [12.5K]2 years ago

8 0

Slope is 1/2
You use rise/run in this case you go up one and to the right two

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Evaluate the expression(-3.8)+0+y for the given values of y.

11111nata11111 [884]

Answer:

y = -3.3 then -7.1

y = -7.1 then -10.9

y = -2.6 then -6.4

y = 1 then -2.8

y = 4.2 then 0.4

Step-by-step explanation:

(-3.8)+0+y can be simplified to -3.8 + y. Evaluate each value for y by substituting it into the expression and solving.

y = -3.3 then -3.8 + -3.3 = -7.1

y = -7.1 then -3.8 + -7.1 = -10.9

y = -2.6 then -3.8 + -2.6 = -6.4

y = 1 then -3.8 + 1 = -2.8

y = 4.2 then -3.8 + 4.2 = 0.4

7 0

3 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$