The issue arises because the string you are trying to print is not a string, rather a float value. Item1, item2 and item3 are strong values (if you type some alphabets in it and not just numbers), but itemonecost, itemtwocost, and itemthreecost are explicitly type casted to float. In line 22, 23, and 24 you’re trying to print a float, by adding it with the string. One cannot add numbers to string. Rather you can type cast the itemcost to string while printing.
Add str(itemonecost) instead of itemonecost in print statement. Do this for other float variables too.
However do note that there are multiple ways to correct this issue, and I’ve just pointed one out.
It is true because a powepoint is a projecter
The answer is true.
Let's say we are calculating the volume of a grain silo where the the width is a constant, but the height can be changed.
In our code we would calculate the volume using something like:
PI * (WIDTH / 2)^2 * height
The variables in all caps would be named constants. Using them makes the code more readable to other people than if we were to just use their values like:
3.14 * (145.75 / 2)^2 * height
Answer:
Explanation:
Following are the Semaphores:
Customers: Counts waiting customers;
Barbers: Number of idle barbers (0 or 1)
mutex: Used for mutual exclusion.
Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves
Shared data variable:
count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.
// shared data
semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;
int count_cust= 0;
void barber() {
while(true) { //shop is always open
wait(customers); //sleep when there are no waiting customers
wait(mutex); //mutex for accessing customers1
count_cust= count_cust-1; //customer left
signal(barbers);
signal(mutex);
cut_hair();
}
}
void customer() {
wait(mutex); //mutex for accessing count_cust
if (count_cust< n) {
count_cust= count_cust+1; //new customer
signal(customers); signal(mutex);
wait(barbers); //wait for available barbers get_haircut();
}
else { //do nothing (leave) when all chairs are used. signal(mutex);
}
}
cut_hair(){ waiting(cutting);
}
get_haircut(){
get hair cut for some time; signal(cutting);
}
Answer:
#include <iostream>
using namespace std;
struct StudentType{
string studentName;
int studentId;
}
int n;
char answer[20];
int main(){
cout<< "Enter the size of the array: ";
cin >> n;
StudentType *student = new StudentType(n);
for (int i = 0; i < n; i++){
int name;
int number;
cin>> name;
cin >> number;
student[i].studentName = name;
student[i].studentId = number;
}
for (int i = 0; i < 20; i++){
cout<< "Enter answers: ";
cin >> ans;
answer[i] = ans;
}
}
Explanation:
The C++ source code has three global variables namely, answer which is an array of character data type, StudentType which is a structure data type and the integer variable n. The main function declares and initializes the dynamic-spaced student array of the structure datatype with the n variable.
