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HACTEHA [7]
3 years ago
12

The class at the top of exception class hierarchy is ..........................

Computers and Technology
1 answer:
Lynna [10]3 years ago
6 0

Answer:

<u>B) Throwable</u>

Explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

There are a wide range of classes on the exception class hierarchy. All the way on the top is the Objects Class but since that is not an available answer we will move on to the next one. The next one is the <u>Throwable</u> class. therefore that is the answer.

**Exception is after Throwable , and Arithmetic Exception is at the bottom.... everything is a class so that is not a part of the hierarchy **

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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4 0
3 years ago
r packages include sample datasets. they also include reusable r functions and documentation about how to use the functions. Tru
Dvinal [7]

r packages include sample datasets. they also include reusable r functions and documentation about how to use the functions.

The above statement is <u>True</u>.

What are R packages?

<u>The statistical programming language R has extensions </u>known as R packages. Users of R can install R packages by <u>accessing a centralized software repository like CRAN</u>, which often contains code, data, and documentation in a common collection format.

The "library" directory is <u>where R </u><u>packages </u><u>are kept in the R environment</u>. During installation, R automatically install a number of packages. Later, when additional packages are required for a particular task, they are added.

To learn more about R packages, use the link given
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7 0
9 months ago
What Network does zoom run on? Does anyone use it (hint Hint)
rewona [7]

Answer:

  • The bandwidth used by Zoom will be optimized for the best experience based on the participant's' network. It will automatically adjust for 3G, WiFi, or wired environments.
  • i use g00gle meet bc zoom does not work on my school macbook...

Explanation:

:)

3 0
2 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
Which query will give the following result when it it applied on table 1????!!!!!
Mandarinka [93]

Answer:

B

Explanation:

You need Name , Age and Gender

the second requirement should only match the last row where age is 20 and gender is male.

thrid requirement of the query is that its syntax should be correct.

Option B staisfies all of required so it is the correct option.

6 0
3 years ago
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