Just compare fractions.
$5.25/x = 8.5/100
Then multiple both sides by 100 and both sides by x;
525 = 8.5x
Divide both sides by 8.5
x ≈ $61.77
Answer:
![\dfrac{1}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
Given,
Total number of trial = 12
Total number of favorable event = 4
Experimental probability of hitting home run is
![P(home\ run)=\dfrac{Favorable\ event}{Total\ trial}](https://tex.z-dn.net/?f=P%28home%5C%20run%29%3D%5Cdfrac%7BFavorable%5C%20event%7D%7BTotal%5C%20trial%7D)
![P(home\ run)=\dfrac{4}{12}](https://tex.z-dn.net/?f=P%28home%5C%20run%29%3D%5Cdfrac%7B4%7D%7B12%7D)
![P(home\ run)=\dfrac{1}{3}](https://tex.z-dn.net/?f=P%28home%5C%20run%29%3D%5Cdfrac%7B1%7D%7B3%7D)
First, subtract 2 from both sides to isolate the variable and you get n/6=-10. Then, since the variable is in a fraction which also means it is being divided, you undo it with multiplication, so multiply both sides by 6 to get n=-60
Answer:
There are 18 pigs and 12 chickens.
Step-by-step explanation:
p = # of pigs
c = # of chickens
I'm assuming each animal has one head and all the pigs have 4 legs and all the chickens have 2 legs, therefore:
p+c = 30
4p+2c = 84
Elimination:
-2(p+c = 30) -2p -2c = -60
4p +2c = 84 4p +2c = 84
2p = 24
p = 12
Now substitute p for 12:
12 + c = 30
c = 18
Check:
4(12) + 2(18) = 84
48 + 36 = 84
84 = 84
There are 18 chickens and 12 pigs.
Hi there! :)
Answer:
![\huge\boxed{2(14x - 41y)}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B2%2814x%20-%2041y%29%7D)
(75x - 67y) - (47x + 15y)
Distribute the '-' sign with the terms inside of the parenthesis:
75x - 67y - (47x - (15y))
75x - 67y - 47x - 15y
Combine like terms:
28x - 82y
Distribute out the greatest common factor:
2(14x - 41y)