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pav-90 [236]
2 years ago
6

If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?

Mathematics
1 answer:
Yuki888 [10]2 years ago
5 0

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

(C_x,C_y) ----> coordinates of point C

we have that

The horizontal distance AB is equal to

AB_x=10-2=8\ units

The vertical distance AB is equal to

AB_y=10-4=6\ units

Find the horizontal coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_x}{CB_x}=\frac{3}{1}

AC_x=3CB_x----> equation A

AC_x+CB_x=8 ----> equation B

substitute equation A in equation B

3CB_x+CB_x=8

4CB_x=8\\CB_x=2

AC_x=3(2)=6

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

C_x=A_x+AC_x=2+6=8

Find the vertical coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_y}{CB_y}=\frac{3}{1}

AC_y=3CB_y----> equation A

AC_y+CB_y=6 ----> equation B

substitute equation A in equation B

3CB_y+CB_y=6

4CB_y=6\\CB_y=1.5

AC_y=3(1.5)=4.5

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

C_y=A_y+AC_y=4+4.5=8.5

therefore

The coordinates of point C are (8,8.5)

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