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Rzqust [24]
3 years ago
13

Which equation below describes a circle. What are the coordinates of the center of the circle

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0
The equation for a circle is
(x - h)^2 + (y - k)^2 = r^2 where r is the radius and the center is (h,k). I don’t see any options for answers though so I can’t help with the last part.
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Can monkeys eat pee when in well that has wet stuff in a zoo with harambe
shtirl [24]

thats funny!! love that!!!! please mark me

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2 years ago
Using the pythagorean​ theorem, if one is given the hypotenuse of a square that is measured as15.56​ inches, what would the meas
dexar [7]
15,56^2=x^2+x^2

242,1136=2x^2

x^2= 242,1136:2=121, 0568

x≈11,003
6 0
3 years ago
How do you solve 2i and 2ii​
natta225 [31]

Answer:

15 and 21

Step-by-step explanation:

Given the n th term formula

T = 2n + 5

To find the 5 th and 8 th terms substitute n = 5 and n = 8 into the formula

T_{5} = (2 × 5) + 5 = 10 + 5 = 15

T_{8} = (2 × 8) + 5 = 16 + 5 = 21

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3 years ago
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What is the greatest common factor of 15 and 21?​
Fudgin [204]

Answer:

3

Step-by-step explanation:

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3 years ago
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A fair coin is tossed three times and the events A, B, and C are defined as follows: A:{ At least one head is observed } B:{ At
kicyunya [14]

Answer:

(a) 1/2

(b) 1/2

(c) 1/8

Step-by-step explanation:

Since, when a fair coin is tossed three times,

The the total number of possible outcomes

n(S) = 2 × 2 × 2

= 8 { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT },

Here, B : { At least two heads are observed } ,

⇒ B = {HHH, HHT, HTH, THH},

⇒ n(B) = 4,

Since,

\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

(a) So, the probability of B,

P(B) =\frac{n(B)}{n(S)}=\frac{4}{8}=\frac{1}{2}

(b) A : { At least one head is observed },

⇒ A = {HHH, HHT, HTH, THH, HTT, THT, TTH},

∵ A ∩ B = {HHH, HHT, HTH, THH},

n(A∩ B) = 4,

\implies P(A\cap B) = \frac{n(A\cap B)}{n(S)} = \frac{4}{8}=\frac{1}{2}

(c) C: { The number of heads observed is odd },

⇒ C = { HHH, HTT, THT, TTH},

∵ A ∩ B ∩ C = {HHH},

⇒ n(A ∩ B ∩ C) = 1,

\implies P(A\cap B\cap C)=\frac{1}{8}

7 0
3 years ago
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