Y=-3x+10 if you take the negative reciprocal and plug in the point to solve for b.
<span>x-intercept = 10/5 = 2</span>
Answer:
See below
Step-by-step explanation:
You multiply the equations by numbers that will give you the least common multiple of the coefficients.
Suppose you have a system of two equations:
![\begin{cases}(1)& 2x + y = 40\\(2) & x + 2.5y = 60\end{cases}\\](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%281%29%26%202x%20%2B%20y%20%3D%2040%5C%5C%282%29%20%26%20x%20%2B%202.5y%20%3D%2060%5Cend%7Bcases%7D%5C%5C)
You can choose to eliminate either x or y.
1. Eliminating x
The coefficients of x are 2 and 1. The least common multiple is 2, so you multiply (1) by 1 and (2) by 2 to get
![\begin{array}{lrcll}(3) & 2x + y & = & 40 &\ \\(4) & 2x + 5y & = & 120 & }\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Blrcll%7D%283%29%20%26%202x%20%2B%20y%20%26%20%3D%20%26%2040%20%26%5C%20%5C%5C%284%29%20%26%202x%20%2B%205y%20%26%20%3D%20%26%20120%20%26%20%7D%5C%5C%5Cend%7Barray%7D)
Then you can subtract (3) from (4) and get
4y = 80. Solve for y.
2. Eliminating y
The coefficients of y are 1 and 2.5. The least common multiple is 2.5, so you multiply (1) by 2.5 and (2) by 1 to get
![\begin{array}{lrcll}(5) & 5x + 2.5y & = & 100 &\ \\(6) & x + 2.5y & = & 60 & }\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Blrcll%7D%285%29%20%26%205x%20%2B%202.5y%20%26%20%3D%20%26%20100%20%26%5C%20%5C%5C%286%29%20%26%20x%20%2B%202.5y%20%26%20%3D%20%26%2060%20%26%20%7D%5C%5C%5Cend%7Barray%7D)
Then you can subtract (6) from (5) and get
4x = 40. Solve for x.