<span>f(x)=3[x-2]
So, f(5.9) = ?
f(5.9) = 3(5.9 - 2)
=3(3.9)
=11.7 = 12
Thus, the answer is 12.
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The probability of NOT getting a 1 or a 9 means you have to subtract those two numbers and how many of each are out. Once you do that, count the remaining numbers, put them as the numerator, and then put the overall total of numbers as the denominator. Your answer is 7/9.
Answer:
44.4%
Step-by-step explanation:
To calculate this, we proceed as follows.
we use the probability equation below;
P(A|B) = P(A and B) / P(B)
Applying the above to the scenario at hand;
P(red | car) = P(red and car) / P(car)
P(red and car) = 40% or simply 40/100 = 0.4
P(car) = 90% = 90/100 = 0.9
P(red | car) = 0.4/0.9
P(red | car) = 0.4444 which is = 44.44% ; to the nearest tenth of a percent = 44.4%
Answer:
3/4
Step-by-step explanation:
The amplitude always comes before the operation(cos, tan...)
