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drek231 [11]
3 years ago
13

A baseball game is scheduled for Saturday. If it rains on Saturday, the game will be moved to Sunday. If it rains on Saturday an

d Sunday, the game will be cancelled. There is a 30% chance that it will rain on Saturday and a 60% chance that it will rain on Sunday. What is the probability that it will rain on both days and the game will be cancelled?
A. 18
B. 28
C. 30
D. 55
E. 90
Mathematics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

A. 18%

Step-by-step explanation:

For independent events:

P(A and B) = P(A) × P(B)

P = 0.30 × 0.60

P = 0.18

There is an 18% probability that it will rain on both days and the game will be canceled.

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2x^3-x^2-3x=210<br> the answer is 5 but I want to know why.
mel-nik [20]

Answer:

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

Step-by-step explanation:

1) Move all terms to one side.

2x^{3} -x^{2} -3x-210=0

2) Factor 2{x}^{3}-{x}^{2}-3x-210 using Polynomial Division.

1 -  Factor the following.

2x^{3} -x^{2} -3x-210

2 -  First, find all factors of the constant term 210.

1,2,3,4,5,6,7,10,14,15,21,30,35,42,70,105,210

3) Try each factor above using the Remainder Theorem.

Substitute 1 into x. Since the result is not 0, x-1 is not a factor..

2*1^{3} -1^{2} -3*1-210=-212

Substitute -1 into x. Since the result is not 0, x+1 is not a factor..

2(-1)^{3} -(-1)^{2} -3*-1-210=-210

Substitute 2 into x. Since the result is not 0, x-2 is not a factor..

2*2^{3} -2^{2} -3*2-210=-204

Substitute -2 into x. Since the result is not 0, x+2 is not a factor..

2{(-2)}^{3}-{(-2)}^{2}-3\times -2-210 = -224

Substitute 3 into x. Since the result is not 0, x-3 is not a factor..

2\times {3}^{3}-{3}^{2}-3\times 3-210 = -174

Substitute -3 into x. Since the result is not 0, x+3 is not a factor..

2{(-3)}^{3}-{(-3)}^{2}-3\times -3-210 = -264

Substitute 5 into x. Since the result is 0, x-5 is a factor..

2\times {5}^{3}-{5}^{2}-3\times 5-210 =0

------------------------------------------------------------------------------------------

⇒ x-5

4)  Polynomial Division: Divide 2{x}^{3}-{x}^{2}-3x-210  by x-5.

                                               2x^{2}                       9x                      42

                                      -------------------------------------------------------------------------

x-5                               |    2x^{3}                          -x^{2}                     -3x     -210

                                           2x^{3}                             -10x^{2}

                                        -----------------------------------------------------------------------

                                                                             9x^{2}                -3x       -210

                                     --------------------------------------------------------------------------

                                                                          42x                              -210

                                                                         42x                               -210

                                      -------------------------------------------------------------------------

5)  Rewrite the expression using the above.

2x^2+9x+42

(2x^2+9x+42)(x-5)=0

3) Solve for x.

x=5

4)  Use the Quadratic Formula.

1 - In general, given a{x}^{2}+bx+c=0 , there exists two solutions where:

x=\frac{-b+\sqrt{b^{2} -4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}

2 -  In this case, a=2,b=9 and c = 42.

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3 - Simplify.

x=\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

5) Collect all solutions from the previous steps.

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

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Answer:

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x² + 6² = 17²

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aivan3 [116]

Answer: 2⁴ * 5

<u>Step-by-step explanation:</u>

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