In the following problem, how many people are in business together? Enter your answer as a number.

Determine the value of x if the mode is 18

chubhunter [2.5K]

Nobody can solve this without any further information?

8 0

2 years ago

1. Curtis was curious about the average height of the different types of plants in his flower and vegetable gardens, so he measu

Nadusha1986 [10]

Answer:

Step-by-step explanation:

hey i got the answer straight from my teach but ony a and c if you have the answer to b let me know : ( A) To determine the mean absolute deviation, first calculate the mean. Find the sum of the values: 8 plus 6 plus 9 plus 6 plus 14 plus 9 plus 5 plus 7 equals 64. Then divide the sum by the number of values: 64 divided by 8 equals 8. The mean is 8.

Next, find the distance of each value from the mean :

|8-8|=0 |6-8|=2 |9-8|=1 |6-8|=2 |14-8|=6 |9-8|=1 |5-8|=3 |7-8|=1

0 plus 2 plus 1 plus 2 plus 6 plus 1 plus 3 plus 1 equals 16. Then divide the sum of absolute deviations by the number of data values: 16 divided by 8 equals 2. The MAD of the data is 2.

C. Since the MAD for the vegetable plant data is so much higher than the MAD for the flower data, this indicates that the heights of the vegetable plants vary more than the heights of the flowers ALSO do you go to k12

7 0

3 years ago

A sociologist wants to determine if the life expectancy of people in africa is less than the life expectancy of people in asia.

Colt1911 [192]

Answer:

The sample statistics are attached.

First, we need to determine the hypothesis.

The null hypothesis should be: $H_{o} : u_{africa} \geq u_{asia}$ .

The alternative hypothesis should be: $H_{a}: u_{africa}$

The next step is about calculating the t statistics based on the samples. This t test will give the probability value or p-value, which determines if there's enough to reject the null hypothesis. The formula we need to use to find the t-value is: $t=\frac{x_{1}-x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1} } +\frac{s_{2} ^{2} }{n_{2} } } }$

Replacing all the values into the formula, we have:

$t=\frac{52.4-58.1}{\sqrt{\frac{(7.4)^{2} }{45}+\frac{(8.8)^{2} }{35} } } \\t=\frac{-5.7}{\sqrt{1.2+2.2} } =\frac{-5.7}{1.8} =-3.2$

Therefore, the t-value is -3.2.

Now, we using a level of significance of 0.01, and a degree of freedom (df) of 34, we use the t-table to find the p-value for this results. (df = N -1; in this case, we take the smaller sample, which is 35, giving us 34 of df).

Therefore, according to the table attached, the p-value is less than 0.01, which is less than our level of significance. This result means that the null hypothesis is rejected. In other words, there's enough evidence to say that the life expectancy of people in Africa is less than the life of expectancy of people in Asia.