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2 years ago

Someone please help! will give brainiest and most points!

Mathematics

2 answers:

Diano4ka-milaya [45]2 years ago

7 0

Answer:Your Answer would be girl, boy, boy (a)

Step-by-step explanation:

Rasek [7]2 years ago

3 0

Answer:

Step-by-step explanation:

(x,y) →(-y,x)

corners are A(2,-1),B(5,-4),C(1,-3)

new vertices are A'(1,2),B'(4,5),C'(3,1)

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(10.01 MC) Marko is playing the video game Fort Attack. The purpose of the game is to shoot invading bandits that are trying to

rusak2 [61]

Angle of fire in degrees = 90 + 30 =120 degrees

Angle of fire radians =180 degrees = π

120* π/180=120π /180 OR 4π/6 OR 2π/3

8 0

2 years ago

Read 2 more answers

How do I graph this linear equation y=3x+4

Talja [164]

First mark a point at 4 on the y axis
Then because the slope is 3 you are going to rise three places up and one place to the right.
Use a ruler to connect the dots.
Hope this helps.

5 0

2 years ago

What are all natural numbers using the digits 7 , 0 ,6 without repeating the numbers

Lelu [443]

Answer:

Step-by-step explanation:

The natural numbers can be :

076

067

706

760

607

and 670

Hope this helps

plz mark as brainliest!!!!!!

7 0

2 years ago

Find the values of x and y<br> X =<br> Y=

labwork [276]

Answer:

Find the values of x and y

X =60

Y=60

60°

3 0

2 years ago

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago